Can Sup Forums do simple math

...

75%

(1 + 2 + 3 ... ) * -6

oh wait at least one not only one i have autism :/

honestly i don't know the answer to this question. is it 50 because you already flipped the other one and this coin has a 50/50 chance of landing

50%

1/3 of course

1/4

h/h
h/t
t/h
t/t

>given the possiblity that one of them landed on heads.

1/2

With the "given" that one of them being heads is a certainty, the other is literally a coin flip, so it's 50/50.

One is given to be 100% and the other is still 50/50 so (1*.5)=.5

33%

WINRAR

What did they land on? If it is grass, I don't want to play

25% you fucking shill slide thread making piece of shit

I don't know man like one in eight? I don't remember the formula for calculating probability in a multi-variable system, and even if I did who gives a shit?

50%
the other can be ignored because its outcome is given

0%
A kike steals both before they land

These events are pretty much independent meaning the the fat one lands heads is irrelevant.
so 50%

the answer is 1/3

TT
TH
HT
HH

4 outcomes, 3 of which meet the precondition, each of which has equal probability. 1/3

also mods need to stop eating hotpockets and do their damn job (for free)

Read carefully. It doesn't say that one landed heads, it says ATLEAST one landed heads.

Possible outcomes that fit this stipulation:
>h+t
>t+h
>h+h

1/3

no its 50%

if one coin lands heads no matter what, than its a 50% chance the other will and thus 50% chance both will

It's not multi-variable though. It's told us there's already a 100% chance of one being heads. So that reduces it to a variable of the remaining coin. Which should be 50/50

The 33% argument is retarded.

>It's another "Sup Forums embarrasses itself" episode

leaf

So it's not simple math it's fucking semantics.

No you can just ignore it. The order doesn't matter.

That is only if the order of the coin toss doesn't matter.

50%

All possibilities from 2 coin flip
HH
TH
HT
TT - not possible as at least 1 was head

This leaves 3 possibilities
Of the 3 remaining, 1 is the HH scenario
1/3 chance

atleast =/= as maybe, at least means there will always be one landing heads no matter what, thats 100% chance of one landing heads.

Possible outcomes:

H H

H T

T H

T T

Outcomes where at least one landed heads are H-T, T-H and H-H.

Out of these possible outcomes, H-H features once. Hence the probability is 1/3.

*semetics

66% or 2/3

your options are either
>one heads one tails
or
>two heads

it's 50/50

Real communism hasn't been tried before.

50% given the given.

no

P(2 heads | >=1 head) = P(2 heads and >= 1 head)/P(>= 1 head) = .25/.75 = 1/3

50 percent kek

H+T & T+H are the same outcome. :/

Depends on which neighborhood the euro lands in.

If muslim, 100%.

1/3

the order does not matter at all.... its still 50% chance in the end both will land heads as long as one always lands heads

>British education

It's either 33%, 50% or 25%

It doesn't mention if the order they land in matters or not, so it is irrelevant.

>given
This isn't a math question, this is a statistics question
P(A|B) = (1/2)/(1/2) = 1/4

it is 50%
one is definitely heads ignore it
the condition is 2 heads
2-1 = 1
chance 1 coin is heads = 50%

duhhhh

Are we guessing the white % here

>outcomes equally likely
>doesn't land on its side

Just admit that you're trying to model some shit you don't understand.

Aeh... fuck off or world equations in a simple understandable way

>tfw Sup Forums is actually retarded

holy fuck I was just beginning to take you guys serious about all this jew shit

>being so autistic you invent math equations out of your ass
It's 50/50 mate. The other coin flips outcome doesn't make a difference. There's a 50/50 chance for each flip

So the coin that lands heads can be ignored.
It's 50%.

thats not true desu

50%, anything else is retarded

well done Muhammad

why use euro coins. #triggered
probability=fucku=0.333....

>plebbit newfag
We don't want you

>H+T & T+H are the same outcome. :/
Guys, these are two different outcomes.

Each is equally as likely as H+H, which is why it's 1/3.

Diaconis is a professor of mathematics and statistics at Stanford University and, formerly, a professional magician. While his claim to fame is determining how many times a deck of cards must be shuffled in order to give a mathematically random result (it’s either five or seven, depending on your criteria), he’s also dabbled in the world of coin games. What he and his fellow researchers discovered (here’s a PDF of their paper) is that most games of chance involving coins aren’t as even as you’d think. For example, even the 50/50 coin toss really isn’t 50/50 — it’s closer to 51/49, biased toward whatever side was up when the coin was thrown into the air.

1/2 divided by 1/2 equals 1/4?

Reminder that no coherent interpretation of probability exists.

Yes it is. You're so stupid you're brain overcomplicates everything's because it thinkable everything is hard to understand. It's 50/50. Neck yourself

Burger is right.

Nah, because the question doesn't say THE FIRST ONE is H, but AT LEAST OF THEM (= first one OR second one) = H.

This is a classic problem and I know it seems obvious that it's 50%, but it isn't and you can see it by drawing a probability diagram.

And no, I'm not making use of gambler's fallacy. The mistake in thinking the answer is 50% is not recognizing that coin 1 being H and coin 2 being H are two distinct event with their own probabilities.