Will you solve it and bang Kuro after school's out?

Will you solve it and bang Kuro after school's out?

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youtube.com/watch?v=uH0hikcwjIA
thinkzone.wlonk.com/MathFun/Triangle.htm
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I will not solve anything and bang her right there, in front of the whole class

Banging her while solving sounds better.

Maybe I'll go back to school and learn Maths again, I really want to fuck Kuro.

I construct the triangle and calculate the angles manually. That's elementary geometry with no trigonometry involved!

a couple of entry-level theorems should do the trick

but really, just ask
I wonder what portion of that board would want to fuck Kuro

super easy mate, no trigs needed. Its just literally calculate every angle you can get your hands on, and keep going on until you get it

I want Kuro to teach me algebra instead.
Geometry is for fags.

Not really, you can't get to the solution only by calculating the angles, since you end up with 4 unknown ones.

It's not solvable without trig, as proven in other threads.

Oh, and to elaborate, the 4 angles, by the rules that governs the angles of triangles, for a system with infinite solutions.

>top left triangle has 50 degrees as an obtuse angle

Hmmm no. You can get BCA since you know CBA and ABC. Then you get BDC with CBD and BCD. Then you get CED.
And you can get BEA since you know EBA and EAB.

So for BEC, you know know everything but Alpha. Simple substraction and you get it.

No, it is solvable. You just have to make extra points and lines.

Explain how you get CED.

Well I would surely love it if banging girls was as easy as this problem ...

it just works.

alpha = ∢ DEA

there, now fuck me

Brilliant. Why didn't I think of just picking random numbers.

Just works? Show us steps

...

Here's a more interesting problem.

now that's my favourite subject

Goat demon with pincers.

Try this one on for size you hopeless virgins.

Infinity.

-1/12

>he thinks it's infinity and not -1/12

-1/12 phaggot

Alright, so
∠CAB = 80
∠CBA = 80
∠C must be 40

∠CAE = 10
∠C = 20
∠AEC must be 150

∠EAB = 70
∠DBA = 60
∠AFB must be 50
∠DFE must also be 50

∠DFE = 50
∠AEC = 150
∠C = 20
∠CDB must be 140
These are the angles for the diamond shaped quadrilateral.

Call ∠CED = X and ∠CDE = Y

20 + X + Y = 180

∠AEC-X = α = 150-X
∠BDC-Y = ∠BDE = 140-Y

(150-X)+(140-Y)+50 = 180

Solve the system and you end up with nonsensical values.

tl;dr, solution is a range of values with the limitation that α cannot exceed 75 degrees

You're smarter than Homu, right?

first, we look at the equivalence
zeta(s) = sum(n=1,infinity)1/n^s
and we plug in s = -1 to get
zeta(-1) = sum(n=1,infinity) 1/n^(-1)
=sum(n=1,infinity) n
=1+2+3+4+...

now, we note that the zeta function also satisfies
zeta(s) = 2^s * pi^(s-1) sin(pi*s/2) Gamma(1-s) zeta(1-s)
so we have
zeta(-1) = 2^(-1) * pi^(-1-1) sin(pi*-1/2) Gamma(1--1) zeta(1--1)
=1/2 * 1/pi^2 sin(-pi/2) Gamma(2) zeta(2)

by eulers solution to the basel problem, we have zeta(2) = pi^2/6, so
zeta(-1) = 1/2 * pi^2/6pi^2 sin(-pi/2) Gamma(2)
= -1/12 Gamma(2)
= -1/12 = zeta(-1) =1+2+3+4+...
therefore, by transitivity and symmetry of equality, we have

1+2+3+4+... = -1/12

Is that the back of the knee?

is 0 a natural number?

...

In some country yes. Mostly no.

I threw a bunch of algebra at the wall and got 120. Is that correct?

No.

...

Steel weighs more then air, so right, faggot.

It is right, but not for that reason

youtube.com/watch?v=uH0hikcwjIA

CAG isn't congruent to CAE in your picture. They share one side, no angles.

Is it because the left acts as like a balloon since the ping pong ball tied down instinctively wants to drag itself up therefore reducing its weight?

i'll just use the binomial theorem then:
we have:

p is prime
n is natural
prove (1+n)^p-n^p-1 is divisible by p

use the binomial theorem on (1+n)^p to get
(1+n)^p = sum(k=0,p)(p choose k)n^k
p choose k = p!/(p-k)!k!
the first term in that sum is going to be p!/(p-0)!0! n^0 = p!/p! = 1
the last term is going to be p!/(p-p)!p! n^p = n^p
we subtract a 1 and an n^p from the (1+n)^p, so all of the terms are of the form
p!/(p-k)!k! for 0 > k > p
p! by definition is a multiple of p, and because k is never 0 or p, each term is a multiple of p
therefore it is divisible by p

that look right?

The right side, even though the steel ball is attached to a string the water still exerts a buoyant force on it which means the ball exerts a downward force on the water.

your drawing doesn't even make sense?

Man i fucking hate when maths starts using letters n shit. Like, maths is just numbers people, no need to complicate things even more. This ain't English.

I'm too dumb for this shit.
Someone give me a common core version of the solution so I feel smart about myself.

>adding every positive integer for infinity gives you a negative fraction

Math is shit.

You fucking retard, holy shit.
It's just A=1, B=2 all the way to Z=26.
Shit's simple, brah.

>he doesn't like math

>end up with some algebra expressions with alpha in them
>excitedly set about simplifying them to get the answer
>0 = 0

Its just when you look at where it hits the xaxis.

No, they are congruent. CG bisects angle ACB, so angle ACG = 10 = angle EAC and ACG ~= BCG thus angle GAC = angle CBG = 20 = angle ACE.
angle ACG = angle EAC, angle GAC = angle ACE, and AC = AC.

Not my drawing, I am too lazy to make one so I used the one that other user post.

When you end up with 0=0 there's technically an infinite amount of solutions.

Or that method simply doesn't work.

ACG ~= BCG
why?

AC = BC, GC=GC, angle ACG = angle GCB so triangle ACG ~= triangle BCG

What a bunch of nerds lmao

pls no bully
pls

Gimme your lunch money, dweeb

>tfw forgot everything relate to math after i have finished my university
Damn, and i used to be a little good at math too

It's divergent, there isn't a sum.
>But muh -1/12...
Is mathematically relevant to the series, but not the sum of it. Fucking parrots.

I want Kuro to sit on my face while she creates lesson plans.

then what the fuck is this

My maths sucks.

Paradox
Depending on what series rules you decided to use in math -1/12
Dont want to get into details

But lets assume you have an infinitely large bar. Friday nights are the non miss event and people will pay anything to get in and an infinite people will show up. The cover starts at 1 buck and increases by a dollar for each person? So you gonna tell me the owner made a net loss of -1/12 a dollar?
Not of course assuming all the cash went black hole or something.

Zeta function regularization.

I remember someone saying this was unsolvable
Can anyone confirm it with AutoCAD or whatever?

No, it is totally solvable. Link to the website with the solution keep being posted. The correct answer keeps being posted. Don't be misled.

And then you stop since it's unsolvable past that.

surely there's a quicker way to do this?
is it important that p be a prime, and not just a natural > 1?

More like water is heavier than air.

1+2+3+4+(nothing) =(nothing)

1+2+3+4+-10=nothing

that was easy

Can't I just be friends with her instead.

I used to sort of like math but 2 semesters of garbage teachers kind of put me off of it and I didn't need anymore anyway.

it is more dense, it does not weigh more

got any of the homu edits?
the more complicated the better

wtf what you said doesnt even make sense, why should I look at the y-axis? And what does that staircase mean? It doesnt even touch the line.
I bet you dont understand the pic either

a is 0 degrees, the triangle is impossible, fuck off.

90* MOTHER FUCKERS, KURO I AM GOING TO DO REALLY NASTY THINGS TO YOU.

It is solveable but only through trial and error.
find the hexagon of e middle point d,c and then solve from there.

It was 20 degree. Just check it with geogebra or something like that. See

Actually the triangle it's quite impossible

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And a rule was broken, ELEMENTARY MATH ONLY. You can't just draw new lines and be like LOL now figure this mess out. 90 degrees is the answer.

Actually the stupid there is you

Show your work. How did you figure out the angles?

That solution only uses elementary GEOMETRY methods.

It is a simple reconstruction of the figure. There is only one possible configuration.

sometimes I wonder how did I manage to graduate anyway lol

If I was a degenerate pedophile sure I would

thinkzone.wlonk.com/MathFun/Triangle.htm

>ABD
>80+60+x = 180
>D should be 40
>D in the image is at least 80

If you had ever opened a maths textbook you would know that these diagrams are not to scale.

Zeta function equals the sum only when Re(s) > 1 you retard rofl.

I'm presuming from that that the answer would probably come about from extending all the line segments out into lines, so that equivalent angles can be deduced from the resulting web.

>∠DBE equals 20 degrees
>a equals 20 degrees
I wonder if that could have been deduced in some way.

...

user are you me?

No Patrick, mayonnaise is not an instrument.

except all these nerds are wrong