you should be able to solve this
never did bother to find out the gender either
you should be able to solve this
never did bother to find out the gender either
Other urls found in this thread:
youtube.com
fictionpress.com
twitter.com
2D > 3D
/thread
Kirisu's box gets filled with black every day.
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so female, or is it a feminine box
wat
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Dum Kurisu poster.
hint: use vectors
obviously tips to the left side
easy/10
youtube.com
Steel ball.
Correct
It's all in the free body diagram
fuggg
That guy is so cringy
Good to know someone has some brains here.
At first I wanted to report the thread for being some unrelated garbage, but then I saw and decided that this one is actually clever.
retard, steel ball is heavier than ping pong ball.
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2.8 > .30
ez
You should be able to solve this.
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01000001 00100000 01100010 01101111 01111001 00100000 01100110 01100001 01101100 01101100 01110011 00100000 01101001 01101110 00100000 01101100 01101111 01110110 01100101 00100000 01110111 01101001 01110100 01101000 00100000 01100001 00100000 01100111 01101001 01110010 01101100 00101110 00001101 00001010 00001101 00001010 01010101 01101110 01100001 01100010 01101100 01100101 00100000 01110100 01101111 00100000 01100011 01101111 01101110 01100110 01100101 01110011 01110011 00101100 00100000 01101000 01100101 00100000 01101001 01110011 00100000 01100111 01101001 01100110 01110100 01100101 01100100 00100000 01100010 01111001 00100000 01100001 00100000 01100100 01100101 01110101 01110011 00100000 01100101 01111000 00100000 01101101 01100001 01100011 01101000 01101001 01101110 01100001 00100000 01110111 01101001 01110100 01101000 00100000 01110100 01101000 01100101 00100000 01100111 01101001 01110010 01101100 00100111 01110011 00100000 01110000 01101000 01101111 01101110 01100101 00100000 01101110 01110101 01101101 01100010 01100101 01110010 00101110
Stop posting that because it's already a thing.
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this shit is why mods delete and ban keit-ai
literally, what relevance does this have to the thread
it's not exactly a good thread but this post is such a complete non sequitur, it reeks of a newfag desperate to try out his new favorite maymay
stop
s t o p
Was posed this question earlier today:
Given any random string of 1 and 0s, consider all the ordered pairs of 1, and 0. Pairs do not have to be next to one another. Let M be the number of pairs that have an even number of digits between 1 and 0, and let N be the number of pairs that have an odd number of digits between 1 and 0. Prove that M >= N always.
Wrong order.
what do you even mean by ordered pairs?
You mean consider all subsets of the string such that the string begins with a 1 and ends with a 0?
>solve this, baka
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Stop posting that because it's already a thing.
-1/12 obviously doesn't everybody learn that in middle school?
That is addition.
That's what I thought, too.
>report a m/a/th thread
How new?