Okay, you guys think you're so fucking smart, here's some math:
If theres two trains, train A and train B.
if train A is in Vegas and train B is in LA
if the distance between Vegas and LA is 260 miles.
if train A is travelling at 70mph.
if train B is travelling at 60mph.
when will the two trains meet eachother if they leave at the same time? and are travelling towards eachother?
show all your proof.
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Its Maths not math you retard
this isnt the ussr. trains no run on time
>9th grade question
use kinematics you brain dead faggot
30mins. Is this supposed to be hard?
260 - 70x = 260 - 60x
70x+60x=260. X=2 hours. 140miles from Vegas in the direction of LA.
Not politics.
2 hours?
60 + 70 = 130
260 / 130 = 2
It takes them 2 hrs to meet, train B is 120 miles from LA, train A is 140 miles from vegas
You must be retarded or 10 if you can't solve this.
They are travelling 130 mph relative to eachother. Since they were 260 miles apart at the start, they will meet 2 hours from the beggining, 140 miles from Vegas and 120 miles from LA.
Now do something worthwhile, like buy a special ed helmet, you need one
Why do maths when this is 5 y/o doodle material
60 -> 60-> 260
Why answer troll/slide threads at all?
Sage.
>260 - 70x = 260 - 60x
wow, cool math there, Einstein. You sure nailed this one!
The picture looks like a high school calculus for me.
A false flag shooting
Checkmate Arithmetic
show all your proof.
You guys do multivariable calculus and line integrals in high school?
1 post by this user
trains never meet. Both are derailed and many niggers where killed.
nigger
this is actually a 6th grade question goy.
confirmed retards so far.
>fucking mods are allowing this so far
pic related is the true final challenge for Sup Forumssters
really? Only a retard would put two trains on a collision course on the same track.
2 hours faggot. I'm in law school and top 10%IQ (not because I took the test but cause I'm top 7% LSAt score). This question wasn't even hard, I was doign it in my head and was prepared to do fractions but not necessary. Please step up your question difficulty.
2 hours
a = 154476802108746166441951315019919837485664325669565431700026634898253202035277999
b = 36875131794129999827197811565225474825492979968971970996283137471637224634055579
c = 4373612677928697257861252602371390152816537558161613618621437993378423467772036
And the solution
ami.ektf.hu
We have an underage person here. This is maths for 10-12 year olds.
Do your thing Janitor.
yet you didn't answer it, with full proof.
are you underage, sven?
i forget everything i learn from math after each year
brute force
1hr: 130 miles covered (70 + 60)
2hr: 260 miles covered (70 + 60) x 2
for something like 214 miles distance
1.5 hour: 195 miles covered (70 + 60) + (35 + 30)
1.6 hour: 208 miles covered (70 + 60) + (35 + 30) + (7 + 6)
1.7 hour: 221
1.65 hour: 213.5
1.66 hour: 214.8
1.3 / 10 = .13
.5 / .13 ~ 4
roughly 1.664 hours to go 214 miles. who needs algebra?
70x=260-60x
x=2 hours
Unless trick question. In that case, fuck you.
You do.
...
my brute force:
260 is the distance from LA to Vegas
travelling towards eachother, when do they meet?
A 70 miles at 1 hour
B 60 miles at 1 hour
both are traveling at the same time.
when the distance is equal both trains meet.
0 + 70 = 70
260 - 60 = 200
haven't met.
70 + 70 = 140
200 - 60 = 140
met
two loops, two hours.
Where x is time in hours
70x + 60x = 260
130x =260
x = 260 / 130
x = 2