can you simplify this conditional?
if (!((!X || !Y) && X))
Do my job for me
Luke Davis
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Alexander Miller
its just like arithmetic, u gotta distribute the !
Jonathan Hall
if(X)
Easton Reed
((X || Y) && !X)
Liam Sanchez
>can you simplify this conditional?
>if (!((!X || !Y) && X))
if !((!X || !Y) && X)
Thank me later
Jonathan Watson
Is there a tutorial or something about how to distribute the !
Owen Foster
if (kys = 1)
Here is your code
Blake Watson
Use the catalog fucklord.
Colton Lewis
William Wood
>using the assignment operator
Ayden Sanchez
>if (!((!X || !Y) && X))
>if ((X || Y) && !X)
>if (Y && !X)
Henry Ortiz
!x && y
John Barnes
So it'll always return true, ya dingus
Jack Perry
> Not even using De Morgan's Law
I know, you are probably shitposting, but come on, you could have done it better
Jayden Rodriguez
Using De Morgan:
if (!((!X || !Y) && X))
if (!(!X || !Y) || !X)
if ((X && Y) || !X)
Truth table:
X Y R
0 0 1
0 1 1
1 0 0
1 1 1
Conditional from table:
if (!(x && !y))
Result:
if (!x || y)
Anthony Rodriguez
You don't even need a truth table, just use the the law of distributivity
Luke Martinez
>it'll always return true
>not knowing assignment op returns rvalue
ishygddt
Colton Ross
Ok then:
(X && Y) || !X
Is equivalent to:
(X * Y) + X'
because:
X' = 1 - X
[/code
then:
(X * Y) + (1 - X)
X * Y - X + 1
X * (Y - 1) + 1
-X * (1 - Y) + 1
1 - (X * (1 - Y))
(X * Y')'
Reconverting to boolean algebra:
!(X && !Y)
and using De Morgan:
!X || Y
That's ok 4ya, buddy?
Leo Cook
I jost got boner looking at that pic
William Barnes
What exactly does ! Represent in this statement
Jayden Sanchez
¬
Henry Lewis
Got Y && !X as well, correct yes? I'm seeing too many different answers and it's making me question myself
Chase Parker
Should be ||, not &&
!((!X || !Y) && X)
!(!X || !Y) || !X
(X && Y) || !X
(X || !X) && (Y || !X)
true && (Y || !X)
Y || !X
Jeremiah Martinez
DeMorgan's Laws
Jaxson Collins
I got this too. Regardless how you put it, X has to be true. Y can be true or false.
Jace Howard
>returns rvalue
Which, in that case, equals to 1 => Statement is always true.
Joshua Brooks
if (!gentoo) do install gentoo
Leo Davis
it depends on the language, you turd
Tyler Howard
Would compilators generate warning for that?
Not to mention it is against any good practice.
Camden Wood
Why would I do your job when a computer can?
wolframalpha.com