Alright Americans, prove us your not as dumb as we all think you are

Alright Americans, prove us your not as dumb as we all think you are.

B?

has to be C

ayyyy

It's a paradox.

At first glance there's a 25% chance since it's 1/4.
At second glance there are 2 answers that say 25%; so it's 50%, or 1 in two.
But as it's 50% it's no longer 50% since there's only one answer out of four that says 50%, so it's back to 25%.

And the cosmic ballet... goes on.

You're a retard if you assume A and D are the same answer.

Like OP and this guy

O

SAY

33%*

E) None of the above

I was trying to copypaste { } with the zero with the slash through it desu

B
>Amerifat intellectuals

Shit question tbqh

Where are the discussion about burger

No. There are two other answers, at that point, it becomes 1:3 and not 1:2

>American education

Dude.

>texadumbs

A) or D).

Now take the next step user.

Ding

It's 25%. You can delete the thread now OP, you faggot.

...

This does not look like a proxy to me

ITT: Nobody actually know if Americans are retarded or just bantering themselves at this point.

>polonium
>france

There are 50% chances you will be correct and 25% chances that you will find the correct answer (if there are only 1 correct answer). This question is stupid, because as I said there are 2 two answers.

1:3 when converted past the 1:2 division line

2 out of 4 never becomes 1 out of 3.

t. wafflenigger

wait, I am not sure if I get it:

ok so there are 3 variables, which is 33.3%, but one variable is there twice

so a + b + c = 100%
b = c and a = 2b or 2c
so lets put it all into let's say b's, since b and c have the same chance, we get:
2b + b + b = 100%
4b = 100%
b = 25% = c
a = 50%

man fuck it, I dont know, I'd make a program in c, give it variables a = 50%, b = 25% and c = 25% that picks them up randomly (taking account %'s) and just let the program run itself for like a bazillion times and than just see which one it picked the most

>which one it picked the most
What?

proof by exhaustion, a common method in mathematical analysis to find a proof, I think wiki should have an article about it in all languages

>people giving the choice options as an answer
this was not the question. it's asked for a chance. the options including chances doesn't change that.

4 options, 2 are the same.
if these two are correct, it's 50%
if they are wrong, it's 25%

>considering citizenship instead of ethnicity
jews discovered most of them

>but one variable is there twice

Why should it be?

Plot twist, none of the answers are right. There is no question

strange game, the only winning move is to not play

50% if a,d
25% if b,c
the choices are a red-herring