someone explain docker to me.
Someone explain docker to me
Andrew Baker
Joseph Harris
Lightweight virtualization.
Lucas Williams
Docker is the future.
circleci.com
Joseph Gray
how use on lincucks?
Henry Morris
>docker
>virtualization
Oy vey.
Dylan Howard
Docker is like a chroot-jail, can be used for developing in isolated environments
Colton Thomas
Obviously you kill the less amount of people.
Dominic Scott
Extremely minimal Linux vms running in isolation
Nicholas Moore
docker is NOT a vm.
It's what
said.
Docker provides a standard way to ship software and its dependencies (called an "image") and runs the software in an isolated environment called a "container."
Sebastian Barnes
...
Dominic Morgan
Okay. Set the switch in the straight position, wait until the first set of wheels successfully pass then flip the switch. Either the train derails or stops and no one has to die.
Lincoln Wright
This train has infinite momentum.
Mason Morgan
An object with a momentum approaching infinite would have a velocity that approaches infinite; a train with an infinite momentum would be too unstable and derail at the first body, or in my scenario at the fork created in the tracks.
Gavin Richardson
Then it doesn't, it gains momentum from each person it hits, restoring the momentum lost from hitting them.
Christopher Ortiz
The trains mass increases as it approaches the switch at a constant speed. If you don't throw the switch its momentum will continue to increase with its mass until it plows you over and then collapses into a black hole killing everyone on both tracks.
Adrian Long
The guy is called Riemann not Reimann
Landon Phillips
> explain docker
It's like LXC, except they use a concept of virtualising not an OS, but an application. There are no "less" or "mc" in those containers, they contain just a shell, an application and a basic set of libs to get it running. Applications communicate via either ports or sockets. It's possible to mount any directory from a host to said containers, even more, it must be done because Docker containters are designed to be non-persistent and any data in them will be lost upon restart.
Also. thehftguy.com
Alexander Campbell
Wouldn't it be better if -1/12 people died, though?
Carter Kelly
Don't let these tards tell you docker isn't virtualization. Docker's virtualization is fundamentally different then traditional VMs. That's why most people automatically regurgitate docker =! VM. There are two types of (hypervisor) virtualization. Type 1 is zen virtualization, which is built from bare metal up. Type 2 requires a host os to run on (linux, mac, windows), and probably the one you're most familar with. Docker is neither; it shares and takes advantage of the kernel's resources, primarily namespaces and cgroups. This is why docker is powerful and lightweight; also why you don't see it fully implemented on fucking retarded windows. In short, docker technically is virtualization, but you should be mindful of the differences. That goi that compared it to chrooting got it right, but I feel like that is too facile of an answer.
Cooper Ortiz
>-1/12th
Flawed math
Lucas Clark
Adrian Hill
I asked my calculus lecturer about this shit years ago
The -1/12th is based on invalid equations
James Jenkins
Zeta function so dumb, all math fag should be in 1+2+3... track to prove only -1/12 people die
Hunter Martinez
Sorry you're brainlets.
Levi Ward
so you ready to prove it on real world. i prepare rail train for you. you can be number 1
Liam Ortiz
any reimann zeta function cannot be applied to realistic terms because there are only a real number of people with no complex constituents. what does i represent then? amount of hair on a person?
Mason Parker
no, it's just complex numbers in real number would be something different
Dominic Parker
>calculus lecturer
Ask from someone who actually knows their shit.
There are two ways of reaching that equation, one is to use nonstandard methods of summation where you generalize the idea of the sum of a series, so you can associate a sum to divergent series.
en.wikipedia.org
The other is based on the Riemann zeta function.
Z(s) is defined to be the sum of 1/n^s where it converges, but Z(-1) obviously diverge, but it diverges in a certain way where you can define a new function Z'(s) where Z'(s) = Z(s) when Z(s) converges and Z'(-1) = -1/12, and Z' is holomorphic in -1.
You can do that everywhere Z(s) diverges except for s=1, so you get a meromorphic function with one pole.
You could also use a version of the Hahn-Banach theorem which makes possible to assign a sum to all series, but that's an overkill and depends on the axiom of choice.
Dylan Hall
No, it's not. You can read up on it here scribd.com