If you have a population of 1000 which contains groups A and B
what is the formula to determine the likelihood that any given individual is a member of groups A and B?
If you have a population of 1000 which contains groups A and B
what is the formula to determine the likelihood that any given individual is a member of groups A and B?
What's her name?
Nevermind, I found it, it's Mayli.
Mayli (Amelia Wang)
2 (1/2A + 1/2B)=1000
Well, if evenly split its just 50%
how would you know what the forumla is if you don't know the ratio of gooks to spooks?
go ask /sci/, i have no fucking idea. Im guessing thats stats and i've never taken it.
y = mx + b
checked and keked
Roll
nice get
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wow, quints
holy shit. thats my highest get ever. A shame i didn't say something funnier
Congrats man.
i just want more of her
Wow, very nice.
A^2 +2AB + B^2 = 1
this is now a get thread
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(Number of people in A and B both) / 1000
You need either the size of A or the size of B else you have no idea. So the chance of being in A is A/1000 and in B is B/1000
OP, I need vid plz
Let P(A) be the ratio of people in A and P(B) be the ratio of people in B.
Then P(A&B) = P(A) + P(B) - P(A or B)
don't worry man. that was funny as shit to anybody who is not from america
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Index of Diversity?
maybe idk
You can make estimates which you essentially to take a smaller sample, but from random places. Not all from one job or neighborhood or anything. And then you just see what the ratio is from there.
gooks to spooks is pretty alright
this, the problem requires more information about the gook/spook ratio
Wow, yet another newfuck that cares about duplicate post digits.
Well that's a surprise.
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this
Noice.
No, if it's evenly split between group A and group B, then the answer is 0%.
gtfo faggot
It's literally just A+B=1000, and you can graph it that way too if a=x and b=y. Not hard.
A could be people with hats and B could be people who ate delivery last night. You're allowed to do both, or neither.
underrated post