Does Sup Forums know
Does Sup Forums know
x = 6
six
ask wolfram alpha
answer is x=666
4x+1 = 25
4x = 24
x = 6
=> √(4x+1)=5
=> 4x+1=25
=> x=6
sqrt(4x+1)-5=0 /^2
4x+1-25=0
4x=24 /:4
x=6
How dumb you have to be so you need ask Sup Forums for help w/ homeworks...enjoy your wellfare dumass
Are you fucking retarded? Go home schoolboy.
6 you nigger
4x + 1 + 25 = 0
4x + 26 = 0
4x = -26
x = -26/4
x = -6.5
6
Next.
-5 squared is 25.
app?
8
How the fuck do you get 25?
photomath
Add the 5 to the other side, then square it to get rid of the root.
are you that stupid or what?
you are mentally retarded (a-b)^2 = a^2 -2ab +b^2
firtst you shoud do sqrt(4x+1)=5 and than multiply
5^2
Do you even math?
No, you just don't know math.
Really?
IIIIII
(a-b)^(1/2) not (a-b)^2 i.e. the 1/2 will just go away once you put it to the power of 2.
It's -5^2.
Which makes 25.
Which means you subtract it from the other side.
-25.
is Sup Forums really tat dumb they can't figure out that X= -0
/4x+1-5=0
/4x-4=0
/4x=4
2x=4
2x/2=4/2
X=2
AWNSER IS X=2
Fuck this. I am writing it on paper
/4x+1=5
4x+1=25
4x = 24
x = 6
I dunno.
sqrt4x+1-5=0
add 5 to both sides
sqrt4x+1=5
x=6
6x4=24
24+1=25
sqrt of 25 = 5
5=5
6, any other answer in this thread is obviously b8
also check my 6
6
fucking retards, x=1
...
/thread
Yup. PEMDAS. In this case:
Exponent. Square everything to get.
4x +1 + 25 = 0
Add to get.
4x + 26 = 0
Get x to one side by subtracting 26 from bother sides.
4x = -26
Then divide to get x by itself.
x = -26/4
Why are you idiots doing this childs homework for him?
Order of operations says you do exponents first.
that's not on paper you liar, that is clearly a screen shot. i'm unsubscribing
x=6
Also, just because we can do something interesting:
√(1+4*6)=5
=> √(1+4(1+5))=5
=> √(5+4*5)=5
=> 5=√(5+4√(5+4*5))
=> 5=√(5+4√(5+4√(5+4*5)))
.
.
.
=> 5=√(5+4√(5+4√(5+4√(5+4√(5+4√(5+4...))))))
still got the right answer, doesnt really make a difference
Yes, I've got no better thing to do.
I couldn't be bothered to find this thread on my phone bro.
Yeah Cauchy and Schwartz didn't know what they were talking about, fuck their inequality, and fuck Young too.
You cannot square added terms individually.
This is a common problem on 7th grade :)
/4x + 1\ - 5 = 0
/4x + 1\ = 5
4x + 1 = 5^2
4x + 1 = 25
4x = 25 - 1
4x = 24
x = 24/4
x = 6
-x = -6
xxx = 666
How is that interdasting?
Because nested radicals are fun.
found the math nerd. This is why I am more of a chemistry guy.
Excuse my ignorance, what is a nested radical and what can they be used for?
It does.
Because if you do exponents first you get -5^2 which makes +25 then subtract to the other side.
But if you add 5 to both sides first you get a completely different, wrong answer.
not to mention that if your process is wrong it's gonna be zero points on a test
nested radical and nth-root is not the same
this is fucking 7th grade math user.shame
>Anonymous
√(4x+1)=5
4x+1=25
4x=24
x=6
X=1 it took me 17 seconds in my head
x=6
Did you drop out of highschool?
Imagine Sqrt(4x+1) + x - 5 = 0
You cant do exponents 1st now.
Sqrt(4x+1) = 5 - x
4x + 1 = 25 - 10x +x^2
lol
dubs speaks truth.
Thanks. Haven't done A level maths for 15 years, so hurts my brain.
I used Gassman equations in Geophysics (again a while ago) always found these very interesting as a real world application
en.m.wikipedia.org
But radical is, no?
>Gassmann
Its german for fart man
How's that job at McDonalds working out for you?
Nested radicals are something that came out of pure mathematics and were brought into focus primarily by the work of Ramanujan.
The ability to create finitely nested radicals were first discovered but not heavily studied when Cardano tried to solve the cubic equation. The Wikipedia example of √(3+2√(2))=1+√(2) is pretty good example of this. These are useful because this method of reduction simplifies the result.
Infinitely nested radicals on the other hand are useful as they can be used to find iterative solutions and they have a strong relation to Galois representations (part of Galois theory).
Some nested radicals are also a bit harder to solve, unlike that other one I made.
isibang.ac.in
No.
en.wikipedia.org
Although it is worth mentioning that you can create nested expressions with nth roots as well.
I've never worked with Grassman's equations. But I have looked at spherical harmonics in geophysics.
Are you stupid? I mean you are showing severe signs of stupid
sqrt(4x+1) = 5
4x+1 = sqr(5)
4x = 24
x = 24/4
x = 6
high school freshman level
Are you dumb
I dont work, 100% NEET. Work is for the slave caste
wat? I did this in 8th grade
>4x+1 = sqr(5)
>4x = 24
That is not possible
To be fair, I didn't learn this until 11th grade, but my school us the 2nd shittiest in the district.
ITT: we solve a kids homework
are you retarded? put a 4x = 25 - 1 in between
OK, Fartman!
As a slightly older user, and hopefully wiser, I'd advise you to change that view and seek out work that makes you happy. Work gives you confidence, self respect and self esteem. Not depending on the state or people around for financial support would make a huge difference in your life, shit, it may even make you happy...
Different school systems.
kek
maybe some user could ask somewhat really challenging
Seeing this while studying non-homogeneous second-order linear ordinary differential equations. Ah, good old times..
Do you want a challenging problem?
Ok, I honestly don't remember when i learned it. I also don't remember what I had for lunch yesterday. Is this caused by smoking weed?
a part of graduate engineers entrance exam. Not really that hard but it's something
That's... that's not possible.....
as long as it's not on the list of Millennium Prize Problems
But there's an unknown variable.....
kk
Give me a moment to format it.
I believe it's:
x=6
4(6)+1=25
Square Root of 25 is 5
5-5= 0
Call me out if I'm wrong but I think that's it.
You can't do it that way. You don't square individual terms.
>√(4x+1) - 5 = 0
The way you're trying to do it:
>(√(4x+1) - 5)^2 = 0^2
>(4x+1) - 10√(4x+1) + 25 = 0
Don't feel like doing the rest because it's a fucking retarded way to do it.
x=6
This is a number theory problem.
Let p(n) count the number of partitions of a non-negative integer n. Let σ(n) be the sum of divisors of n, with σ(0)=0.
Prove pic related.
2pi is 360* right?
How about this?
√4x+1 - 5 = 0
√4x+√1-√5 = 0
2x + 0 -2,5 = 0
-0,5x = 0
x = 0,5
easy
who is this Sup Forums?
oh for fuck's sake if you remove a square root you gotta put the number between modules ("|4x + 1|")
jesus
add 5
square both sides
subtract one from both sides
divide by 4
your left with
x=2/3 or 4/6
I guess the proof uses induction
P(1)=1
1/1 * (p(1-0)*1 + p(0)*0)= 1
this!
correct