1 = 0.99999999

1 = 0.99999999...
Prove me wrong, faggots.

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We can't.

ask /sci/, they're good at these things

Well numbers arent "real" so 1= 0.9999... is a meaningless statement.

1 = 1
1 - 1 = 0

0.9999999999... = 0.9999999999...
1 - 0.9999999999... > 0

they aren't the same

there. proven

you didnt prove that 1-.99999999 is > 0

OP here:
Bonus points if you can prove that

1+2+3+4+5...=/= -1/12

if the "..." at the end of 0.999... has the context of a limit process, then yes, absolutely, 1 = 0.999...

if the context is simply a comparison of real numbers, then no, 1 does not equal 0.999 repeating. The proof is that you can construct a number between 1 and 0.999... by the addition of an infinitesimal (as per Robinson's seminal work on Non-Standard Analysis).

1 > (0.999... + dx) > 0.999...

oooooh i get it. since the .999... goes on for infinity you have to keep adding 0.00's until you get to the end to ad the .1 but since its infinity where does the 1 go?

at the end, it's infinitesmally small

ya thats one way
but the common way is

.9999... /3 = .33333333
.3333333=1/3
1/3 * 3 = 1

but... you cant.....no.... its not equal to one... its......nooooooo

>0.333333....= 1/3
Being this stupid
0.333333....×3=0.9999...

actually, at the end, it is not infinitesimally small, unless you specifically add infinitesimals by invoking the calculus. It takes an infinite amount of infinitesimals (thus the name) to make even the smallest finite number.

That's why the expression 1 > 0.999... holds true if discussing the numbers as a completed set: {1} > {0.999...}, because infinitesimals are not being invoked in this case.

It's all about the context.

1/3 * 3 = 1
.3333....=1/3
which part dont you get?

What is the real world equivalent of 0.999 repeating?

Nope. You've switched horses in midstream for your argument, which is why your argument looks good on the surface.

You make the context mistake of saying 0.333... = 1/3, which is a circular argument, being the thing trying to be proved in the first place.

>1/3 fractions meme
end yourself faggot

there is none .99999... implies that you took an infinitly small portion out of an object and we cant do that (yet at leaast)

1/3=.3333333... has already been proved im just showing you that it also shows .9999...=1

explain to me why it's wrong

no. 1/3 = 0.333.. has not been proved. It is the same question as trying to compare a whole number to an infinitely repeating decimal expansion as originally posed: 1 vs 0.999...

but it makes it sound convincing by changing it a little

22/7

can you back that up?
because you can type 1/3 in a calculator and get .333333 repeating

Prove yourself right instead. This isn't how arguments work

>Prove I'm not god, pro-tip, you can't.

you can prove it in 5 seconds with long division

wow I actually know this one, gimme a sec.

It's a ramanujan theorem but It's beyond my comprehension

enough with the bullshit
youtube.com/watch?v=G_gUE74YVos
End thread

I hope this is bait.

Dipshit simple way of proof is

1/9=.11111111
2/9=.22222222
therefore 9/9, while equivalent to 1, is also .9999999999

?

>dipshit simple way of proof is
Yes, your proof is one dipshits would accept.

the law of identitys states that a=a. you have stated a thing where a != a and ask us to prove you wrong. go fuck yourself.

Thank you for saying this user

/thread

Op is a fag

well it does
1/9=0.111...
2/9=0.222...
...
8/9=0.888...
9/9=0.999... OR 1
Because anything over itself is 1.
9/9=1

Okay. Do this for me. I would like you to write a number for me. Please express the number that has the most repeating nine's in it, that does NOT equal 1.

I will wait.

No mate - you're the one with shit for brains

You people are fucking stupid. If i have two identical apples and i take a bite out of one of them, BUT IT'S A REALLY SMALL BITE, are the two apples still the same.

you are taking a particle i might say, and yeah, 2 apples equally.

We know that 0.9 recurring never reaches 1, in the same way we know the curve of y=x^-1 never touches the axis, even though it gets infinitely closer

if you take 2 bite that are infinantly small which is impossible because matter is quantisized then they would

easy square them
1^2 = 1
.9999999999^2 = 0.9999999998

.99... != 1

1 - .99 = .0...1

apparently 99% of Sup Forums failed high school

argumentum ad hominem

you niggers need calculus

This is probably the most brilliant proof that 1 =! .99...

A good 60% probably still is in high school

you dont math very often do you...

If 0.999... and 1 aren't the same number, than what number is in between them? There isn't one. Therefore, 0.999=1

too bad that there's infinitely many 9's, so that that 8 never actually occurs

...

1 = 1

0.99999999... = 0.99999999...

That simple.

It's close enough.

I think the flaw lies with our understanding of numbers, conceptually 0.999... Is not the same as 1 they are different even if they are infinitely similar, there is still a discrete fundamental difference in their values

between .999 and 1 is .9995
between .9999 and 1 is .99995
and so on for ever and ever

Yeah there is a number between them, in fact there are infinite amount of numbers between them, different rates of infinity produce different infinitys

...

If you were to add an infinite amount of 1's and add an infinite amount of 0.9999.. 's you would end up with two numbers with an infinite gap in between. If they are the same you would end up with the same number. Therefore 1 is not the same as 0.9?9...

it's all about context.
As a Calculus limit process, 0.999... DOES equal 1.
As a -number- , 0.999... does NOT equal 1.

/thread