Given the function f(x)=−8+x^2, calculate the following values:
f(x+1):
f(x)+f(6):
wtf pls hlp
Given the function f(x)=−8+x^2, calculate the following values:
f(x+1):
f(x)+f(6):
wtf pls hlp
Given the function f(x)=−8+x^2, calculate the following values:
f(x+1):
f(x)+f(6):
use the function retard
f(x) = 8+x²
f(6) = 8+6² = 8 + 36 = 44
f(x+1) = ( 8 + x² ) +1 = 9 + x²
what are you op , a fucking bag of shit ?
Nope
Dubs are right
are you black
its -8 , and you call op a fucking bag of shit top kek
also f(x+1) = -8 + (x+1)^2 = -8 + x^2 +2x+1 = -7 +x^2 +2x
f(6) = -8 + 6^2 = 28
(X+1)(X+1)=x^2+2x+1
oh i forgot f(x) + f(6) = 28 -8 +x^2 = 20+x^2
hmm yea sure didn't saw the ( - ) ; still it's fking easy ...
could you have found a crappier rescale image of this perfect specimen
>op's retarded question
>filename
checks out, confirmed nigger
Virgin detected.
>not asked
you want some attention ?
It was asked retard reread the OP
How do I know whether the corresponding curve defines y as a function of x when looking at graphs?
>that shit tier picture lol
Someone drew a 6 or a 9 on the floor , there is only one choice
this for example
yup indeed , my mistake :) sorry for inconvenience bro
Since we are doing Math,
Can u solve the Limit where x^2+y^2 goes to inf
f = sin^2(x+y) / ((sin^2(x)+sin^2(y))
sorry correction, limits goes for (x,y) to (0,0)
g(in red)
Estimate the solution of the equation: g(x) = -4
For y to be a function of x each x has to correspond to exactly one output. That means that you cannot have more than one y value for any given x.
5
and -5.5 probably as well
Thanks a lot for the answer, that's pretty easy to understand. But then they post a graph like pic related, how the hell am I supposed to see if they're over one another or not without details...
f(x+1) = (x+1)²-8
f(x+1) = x² + 2x +1 - 8
f(x+1) = x² +2x -7
f(x) + f(6) = −8+x² + −8+ 6²
f(x) + f(6) = x²-16+36
f(x) + f(6) = x² + 20
this
all other responses are troll or dumb