I am not going to ask how many bowling balls there are, but how many are there?
I am not going to ask how many bowling balls there are, but how many are there?
1
285
Bottom row has 9! (9 factorial) balls:
9 on the right edge + 8 in the second row + ...
Second row has 8!
....
(9!) + (8!) ... + (1)
285
165
215
There's only one and the rest are part of your imagination. Now let's all vote Hillary you cucks
EXACTLY HALF OF THE CUBE, so if the cube is 9x9x9=729 then half of that would be 364.5, now fuck off with this shitty thread
+assuming there is half a ball in the batch
This is why America will not be great again.
91
this guy is right
Fucking faggot can count 9 balls but cant realise there are only 3 fucking sides.
I believe this user is right...
I believe this user is right...
Factorial is multiplicative, this is additive. It's 165.
81 + 64 + 49 + 36 + 25 + 16 + 9 + 4 + 1= 285
Bottom layer alone is 81
nvm this is very wrong its 165
215 niggers
There are 82 visible
1 + 3 + 6 + 10 + 15 + 21 + 28 + 36 + 45 = 165
For a square base the bottom layer would be 81, 9*9=81, its definitely not a square!
S=0
For N=1 to 9
S=S+N^2
Next N
Print "OP has ";SUM;"balls."
Type this Exactly into any old computer.
That's not a square
Those Ataris and Commodores doesn't exist any more, but you can find nice emulators for it.
im pretty damn certain its 3 sides. which would mean 165
start from the top down and work out the pattern
1:1
2:3
3:6
4:10
5:15
6:21
7:28
8:36
9:45
Then add the layers together
wait, op is shenanigansing us guys.
165 + another hidden layer of 45 = 210
the more bumbest way to found out how many balls they are
>pic related
Tetrahedral number:
x = (n*(n+1)*(n+2))/6
9 layers
x = (9*(9+1)*(9+2))/6
x = 165
Too fucking many.
For each layer: (n+n^2)/2 (=Gauss)