Well?
Well?
Harsh roll mein friend
You're fat.
21
15+5+1+1=22
21
Threads over kill yourself faggot nerd
This
kys
Finally, some non retarded anons.
Got three wrappers left m8
Have yourself an extra one
You're right
15+5 = 20 you retards.
Please tell me you're only pretending to be this stupid
right after I posted 21 I realized it was actually 22
...
if 1 chocolate is 1 usd and you have 15 usd that is 15 chocolates. if 3 wrappers is 1 chocolate then thats 15 divided by 3. you dumb cunt.
can't you ameritards count?
15 chocs = 15 wrappers.
15 wrappers = 5 chocs.
5 chocs = 5 wrappers.
5 wrappers = 2 wrappers and 1 choc.
1 choc = 1 wrapper
2 + 1 = 3
Those 3 wrappers turn into one chocolate. You just got 22 chocolates.
How many wrappers do you get from those 5 extra candy bars user? and How many wrappers from them?
That leaves you with five wrappers
Three of wich you exchange for a chocolate
Eat it and that leaves you with 5-3 = 2 and add the bar you just ate 2+1 = 3
Exchange the wrappers for a bar and that gives you the last one
Hence 22
Again stop pretending you're this stupid user
69 xD
15 + 5 + 1 + 1 = 22
15 is the first batch. You end up with 15 wrappers and you can replace every 3 with a chocolate bar:
15/3 = 5
Exchange 3 of the wrappers with a chocolate bar:
5-3 = 2 wrappers left.
Now you have 1 extra wrapper:
2+1 = 3
3/3 = 1
forigve my drunken math
22 chocolates total, 1 left over wrapper
>69 xD
It's 20, you choco-cucks.
29.
chocolate consumers can't solve this.
17 but i don't buy it
Over 9000
chocolate consumers can't solve this.
22 but i don't buy it
15. No one said the chocolates came pre-wrapped
lel
(0,0) -> (15,15) -> (5,20) -> (2,21) -> (3,22)
22 chocolates.
Plus you have 1 wrapper left
...
so you proceed and team up with somebody and you get your 1/3 split ?
22 consumers can't solve this.
chocolate but i don't buy it
Easily solvable in a general way: n = (x mod 2) / 2 + 1.5x - 1, where x is your amount of money. With x = 15, that gives n = 22.
Wrong. Assuming 8% sales tax you can only buy a max if 13. This will yield 4 on the initial wrapper exchange and 1 on the second exchange.
WHAT KIND OF RETARDED STORE WHO GIVES CHOCOLATE FOR FREE FOR 3 WRAPPERS LOL
But then you would each have 1/3 of a wrapper which you could pair with 8 more people for another chocolate. So the answer is infinite chocolates.
who says the $1 isn't incl. g.s.t?
Diabetes. Because you just ate 21 chocolate bars on the spot just to get the 22ed bar.
15
OP here. I'm currently entering a sugar coma. Please stop sending chocolates.
22 chocolates can't buy this.
But I don't solve.
Nevermind.
Delete this.
ThisAlso, in the US, food is not taxed.
Here's a helpful computer program:
Prelude> let solve m w = if w >= 3 then 1 + solve m (w - 2) else if m > 0 then 1 + solve (m - 1) (w + 1) else 0
Prelude> solve 15 0
22
Not even 22 chocolates can solve this, and i am not buying this.
What about whoring yourself out to the guy who's selling the chocolate?
>in the US, food is not taxed
Ok then, guessing you are not an economics major. Or someone who wins at board games a lot.
Or if that program was too helpful,
Prelude> let y f = f (y f) in y (\f w m -> if w >= 3 then 1 + f (w - 2) m else if m > 0 then 1 + f (w + 1) (m - 1) else 0) 0 15
22
first pass: get 15
second: get 5
third: get 1 2/3
fourth get 5/9
fifth: get 5/27
sixth: get 5/81
seventh: get 5/243
eights: get 5/729
ninth: get 5/2187
...
without rounding you can get an irrational number of chocolate for $ 15
>series of rational numbers
>you can get an irrational result
Oh well.
JEWS
it is an infinite series but after this point you need a microscope to measure amounts
>buy one chocolate
>divide chocolate bar infinitely
>have infinite chocolates
>have $14
>profit
An infinite sum of rationals is also rational. We know this because the sum of two rationals is rational, and at no point in the infinite sum will that stop being true.
Has anyone answered "seven" yet?
you are saying that there are no irrational numbers? en.wikipedia.org
$15 gets you 15 chocolates
15 wrappers get you 5 more chocolates
5 wrappers get you 1 more chocolate with 2 wrappers left over
1 new wrapper plus the 2 leftover wrappers gets you 1 last chocolate
15 + 5 + 1 + 1 = 22
No, I'm saying that I have a rudimentary understanding of set theory. For example, en.wikipedia.org
How do you represent a sum of an infinite series as the ratio of integers?
Well, if it's convergent, then the number it converges to, and if it's divergent, then as positive or negative infinity. Have you taken calculus?
go back to school and learn more then
en.wikipedia.org
15 original chocolates
15 wrappers=5 extra chocolates
5 extra wrappers=1.6 chocolates
1 extra extra wrapper+2 leftover extra wrappers=1 chocolate
22 chocolates with one wrapper left over
15