Bet 5 Trump Coins that none of you faggots can solve this

Bet 5 Trump Coins that none of you faggots can solve this
>Every possible getting equation wrong is a bonus 5 Trump Coins raising the jackpot
>Get it right, and Kek will bless you with a girlfriend and the jackpot of Trump Coins
100 Trump Coins and any celebrity the winner wishes shall die.
Shadilay.

ok

What even is the question? So far you've only set up a situation. Either way you would pull the lever if the goal was to kill as little as possible and do nothing if it was to kill as many as possible

you're a question

pull the lever. zero chance at all at minimizing casualties if you don't.

if it leads to more people, tough shit. I didn't pull any lever. what lever?

Just leave it

QUESTION: Is it wiser to pull the lever, or to leave it?I'm OP

multitrack drift, 15 kills!

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If you do nothing the trolley will kill 5 people, but you will not be directly responsible because you took no action. It can still be argued that your inaction makes you culpable, but pulling the lever means that either one person or 9 people will die. In either situation you are directly responsible for that loss of life because you were the one to pull the lever. Therefore, it is best to do nothing and let the trolley continue on track C. It is not your place to decided who lives or dies, especially if your choice will potentially endanger more innocent lives.

>wrong
>moral dilemma
pick one

THIS IS NOW A GET THREAD

How the fuck my dick got stuck

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comparing track a to the other tracks it wouldnt even be able to go on the track, like look how shitty that track is..
solution: pull lever, worst case it goes b and kills one, best case it goes a and goes off rails before it hits anyone

you browse Sup Forums. never know what fetish you'll have next.

Tracks > Traps

JACKPOT IS =85

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Pull the lever when its between the wheels causing the train to derail

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If you don't observe the train, it's doesn't kill anyone.

Schrodinger's cat

Pull it! Kek will guide the Trump Trolley with his high energy!

105 TRUMP COINS TO THE TRUE FOLLOEER OF KEK!
SHADILAY!
Choose who shall die wisely...

Pull lever and don't look at train. Therefore both. You eliminate C leaving A and B still viable.

What if you pull the lever before the train gets to the track change and see which way it goes and then decide from that point on. If it goes to track A pull the lever back if it goes B let it stay there.
(Never said you couldn't pull the lever back and forth)

Praise him!

Scenario one: Don't pull lever ten times in a row. 50 people die.

Scenario two: Pull lever ten times. 50% probability trolley hits B, 50% probability trolley hits A. So 5 times it hits B and 5 times it hits A. That's 45 people plus 5 people so 50 people total.

Statistically speaking, whether you pull or don't pull, the expected value (EV) of how many people die is the SAME. So you might as well not pull the lever and keep your hands clean.

Do you mean that the trolley carries some magnetic moment and the junction is meant to be a Stern-Gerlach machine with the trolley prepared in an orthogonal spin state?

In that case, the trolley's wave function would take the form
1/√2|A_t>+1/√2|B_t>
where A_t and B_t are the paths as observed by the trolley

Now I suppose you want us to carry this analogy further and say that the trolley interacts with either the one person or the nine people. Although, I suppose you would like us to assume that this is a weak interaction such that it does not collapse the trolley wavefunction before we look? But also be coupled to the person/people such that looking also collapses their wavefunction?

If the trolley interacts with the people strongly, then it's much more likely that the trolley will find itself on track A since there are numerous people to interact with and they seem to be closer on the track than the person on track B.

But in a magic fairy land where trolleys interact weakly with people so that the wavefunction does not collapse, upon observation, our above wavefunction collapses according to:
()
with probability distribution
()*(1/√2|A_t>+1/√2|B_t>)

Where A_p and B_p are the tracks as observed by the people, D is an operator which returns the number of deaths given the track (position) of the people and the trolley, and * denotes the complex conjugate.

The expectation value for D is therefore:

=()*(1/√2|A_t>+1/√2|B_t>)
=()
=1/2+1/2+1/2+1/2)
=1/2+0+0+1/2)
=1/2(1)+1/2(9)
=5

And on average, you kill the same number of people as not pulling the quantum lever.

KEK

KEK

DANKER THAN SHREK

VOTE FOR TRUMP OR GO TO HECK

Sooo by that same logic, just because you don't observe people being murdered by muslim terrorists, then they really didn't die right? The news lies about every bad thing in these world that happens and there's no proof if you didn't see it with your own eyes?

Of course, we have no reason to believe that there is a 50/50 chance of the trolley following either path upon interacting with your quantum lever. All of this started with the assumption of a state which was orthogonal to both options.

Well, by that logic if you don't observe people being murdered by muslim terrorists, they both are and aren't being murdered. You are their murderer when you look and collapse them into only one option.

seriously? you have never once looked at at a pair of shiny rails sitting on a string of sexies ties and thought to yourself "man - I want to fuck the shit out of that"

How do you even call yourself a man?

>Pull lever slightly
>Observe the small change
>Pull the lever so the track goes to whichever one you choose

This user does have a point.