Can you solve it?

Can you solve it?

14

18cm2

24

Its clearly bigger than the 16 one you tard.

All sides are equal and are worth L. The area of each quadrant is L^2 and the entire area is 4L^2.

I will call the area of each quadrant 'a'.

A1 = 28 = a + A - B;
A2 = 16 = a - A - D - E;
A3 = 32 = a + B + C + E:
A4 =? = A - C + D;

Right now you have 4 equations with 7 unknowns.

But A, B, C, D and E you can put them in function of the putative convergence (let's call it x, y).

So 5 of the unknows can be replaced by 2 unknowns, and we are left with 4 equations and 4 unknown.

24

20

15 cm2

>Can you solve it?
No. Not enough info.

20

25

Area of square in odd number, gl out there.

>Can you solve it?
Correct answer:
No, I can't solve it.

Don't know, don't care, checked for trips

a square of 3 x 3 would have an odd number area.

20

the sides are 10 cm long, so the remaining cm from the whole thing would be 24

Sure.
Save the image, se paint to color one of the fields red e.g the 26 one. Now color the field with the ? Green.
Use a python script to count the red pixel. Divide 26 by this count to get a factor. Now multiply the count of green pixels by that factor.
Voila.

im guessing 24

>sides = 22 total
>area = 484 cm^2
>484 - (28+16+32)= 408
408 cm^2

It's most likely 24, but we do not know the exact value of x unless we physically measure the angles. All that is known for sure is that

4x^2 = 76 + ?

Where x is the length of the equal sides

I got it I got the answer its 439.62. Solved.