Find a number that fits between 0.999... and 1.
Find a number that fits between 0.999... and 1
Jacob Wilson
Other urls found in this thread:
Aiden Walker
OP's penis size.
Jacob Hall
0.9999
Eli Kelly
0.9991
Joseph Cox
0.999909
Mason Harris
...
Aiden Perry
it's repeating, but cannot be one. Therefor it's everything and nothing
∞
William King
0.9999...1/2
Zachary Ramirez
0.9... +i1
Angel Wood
...
Leo Martinez
no its right
youtube.com
Josiah Reyes
0.000...n...0001
Camden Thompson
1/3 * 3 = 1
.333... * 3 = .999...
1/3 = .333...
Jason Reyes
{ }, because 0.99999... = 1
Wyatt Diaz
it's a blowout OP, you can cease your repetitive posting of this thread now
Joseph Walker
...
Juan Kelly
okay but can you prove that 0 and 1 are not the same number?
Oliver Robinson
if 0.999... = 1, then does 1 = 1.000...1?
William Gutierrez
>proof by induction
That proof is bullshit. It would work with any number.
Jaxson Bailey
Because then after infinite steps, 1 = 4.999...
1 = 5
Jacob Baker
are you retarded? just because a number follows another number doesn't mean they are equal. It's like saying that 1=2 in the integer set.
Leo Smith
(0.9999... / 2) + 0.999....
Adrian Bailey
0.999... = Sum {n=1}{inf} 9 * 0.1^n
for There to bei a Nummer x with 1 > x > 0.999... , There needs to exist real Nummers a and b with a>0 , b>0 and 0.999... + a = x and x + b = 1.
Thus a+b = 1 - Sum {n=1}{inf} 9 * 0.1^n = Fac {n=1}{inf} 0.1 . As a+b > 0 There is a m > 0 with Fac {n=1}{m} 0.1 < a+b. And Fac {n=1}{m} 0.1 > Fac {n=1}{inf} 0.1 . Therefore a+b > Fac {n=1}{inf} 0.1. This is a contradiction therefore it is impissible. QED
Brayden Brooks
1-0.999.../2
John Wilson
appropriate notation for rational numbers:
(1/3) + (1/3) + (1/3) = (3/3) = fucking 1
unappropriate notation for rational numbers :
0,33333.. + 0,33333.. + 0,33333.. = still fucking 1
0.999999... =/= 1 als long as post decimal positions are NOT infinite.
thats it. no inconsistency, no discussion. its definite.
Juan Turner
is there a number between 1 and 1?
if so prove. if not prove.
I know answer see if Sup Forums is smart enoug
John Sanchez
This is prove that there isn't one
Xavier Torres
Easy. After the very last 9, add a 5.
Owen Hughes
There is no last retard
Isaac Flores
can't deny a full house
Brayden Martin
I know. I just wanted to make you mad.
Brayden White
normalfag
Asher Campbell
That is actually an axiom, so it can't be proven
Lucas Moore
0.999... < 1
therefore 0.9999 =! 1
done.
Josiah Wood
Let x = .999 recurring, and let y = 1
Then let z = (x+y)/2
If x = y (which it does), then x = z = y. But if x < y, then z fits between them. Either way, z fits in.
Julian Young
1/∞
Wyatt Anderson
_
0.95
Jayden Ross
1/infinity is 0 (or as close to 0 as you can get), which is less than 0.99... so does not fit between the two.
Christian Young
(1 + 0.999....)/2
how is this hard easy
Jace Johnson
Except that 0.999... < 1 is a false premise, because there is no number between them.
Continuity is defined thusly:
∀x,y | x < y, ∃z. x < z < y.
Which mean that if there is no z, x >= y.
Anthony Clark
no you retard
Elijah Robinson
are you stupid? They all fit between .9 and 1
Juan King
you can't because 0.999... = 1
Joshua Ortiz
Can't you see the fucking vinculum you fucking retard
Leo Long
Subtracting different numbers from eaxh side of the equation is an illegal operation.
Xavier Mitchell
Dude, I'm telling you. It doesn't matter what they put above the 9, there's plenty of space to throw whatever numbers you want between them. Hell I could probably put a swastika between them if I wanted to.
Chill your fucking tits m8
Noah Turner
It means 0.999... up to infinity. Which mean that you can't put any number between them. Here is a simple demonstration:
Let x = 0.9999999...
10x = 9.99999...
10x - x = 9.99999... - 0.99999...
9x = 9
x = 1
See?
Eli Martin
I can't tell if I'm being trolled, or if you're honestly this fucking oblivious.
I was making a joke dude, and I tried my damnest to make it as apparent as possible.
Christopher Jenkins
I'm just that fucking oblivious.
Alexander Cox
This is actually not an axiom.
Axioms are either peano's axioms, or ZFC axioms
Easton Hughes
there you go OP
Caleb Walker
OP's IQ
Evan Harris
>no
>doesn't explain why
cuck
Jack Edwards
>Axioms are either peano's axioms, or ZFC axioms
>either
>or
If you actually think that all of mathematics is based on these two axioms, you're retarded.
Eli Edwards
Underrated
Adam Myers
0.999... < 0.999... + 1/inf < 1
Owen Garcia
1/3 = 0.333...
3/3 = 0.999...
3/3 = 1
Brayden Harris
1 / 10^n
Ryder Myers
That's incorrect usage of algebra, but nice try dude.
Juan Powell
From what ass did you get 4.999... I'm first place? Elaborate.
Cooper Jones
1-(1-.999...)/2
Ayden Kelly
1 - (1 - .999...)/2 = 1 - 0/2 = 1
Justin Kelly
Well if 0.999... = 1, then isn't it possible that 1 = 1.000...1, then 1.000...1 = 1.000...2 which is also 1 = 1.000...2
Then you repeat that infinite amount of times and you'll get to 1 = 1.999...
And yeah
Jordan Williams
How can there be a number after an infinite amount of zeros?
Mason Baker
Mathfags fuck off already
Michael Fisher
are you retard?