Help me with this one please Sup Forums

help me with this one please Sup Forums

Other urls found in this thread:

onemathematicalcat.org/algebra_book/online_problems/dom_range_function.htm
en.m.wikipedia.org/wiki/Imaginary_unit
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3/2 you retard

Nigger

-(3/2)

fucking amerifats

471.0913398

-3/2

its -9/6 because the square root cancels out the ^2

/thread

how old are you?

someone never took AP math

wolframalpha.com

-9/6 wich is the same as -3/2 and -1'5

fuck ap dude that's shit you learn in like ninth grade

you can't have (-) under a square root....

...

>Two negatives make a negative
Fucking kikes

> calculus
> 9th grade

think again fag

It's algebra, not calculus

Also, it's possible to learn calculus in 9th grade if you're sufficiently advanced

but it isn't under a square root, it's a 2/2 exponential, which simplifies as a 1 polinomical

its fucking 3/2 faggots if you don't agree you are literally retarded stop arguing and let the thread die

B E D M A S

-1/2 you fucking retards

here are some examples

fucking nerds lol

BUT YOU CAN'T HAVE A NEGATIVE UNDER A SQUARE ROOT YOU IDIOT

well I'm doing math teaching in college, so I guess this question is pretty simple for me

also, there are negative roots, these are known as complex (or imaginary)

that's the correct answer you group of fucking faggots. the - is into the parenthesis so basically you have to do (-9/6)*(-9/6) that is fucking positive

1.5

±3/2

This

Why doesn't anyone know how to fucking math anymore?

except you carry the - last because it is multiplication by -1.

Imagine the root as an exponent. The problem can be written as -(9/6)^(1/2)(2) = -(9/6)^1 = -2/3

-3/2 I mean*****

what's your problem, dude?

da 3/2 putos subnormales

Estos dos saben, el resto sois imbéciles

the answer is -3/2 wheter you like it or not, but here's a more interesting question:

Is f(x)=0 same as f(x)=(0/x)

If I solve it visually by first multiplying (-3/2) by itself, the answer is 3/2

If I solve it by converting to exponents, then the answer is (-3/2)^2^(1/2) = (-3/2)^1 = -3/2

Guys did we just break math?

yes

>wolframalpha.com

was the problem that you didn't know how to input it into WA or a calculator right?
>sqrt(((-9/6)^2))

but when x=0 in f(x)=(0/x) you have a problem!

You should learn to scroll.

um, you didn't specify limits faggo
come back at me again when you know real maths

innermost grouping first.

i saw the solution posted but no explanation of why OP couldn't use a calculator or the website himself

you have to specify the domain of the function. go back to school

Si x=0 --> no Existe
Si x no es 0 --> 0 = 0/x

Se hace asi
[((-3/2)^2)^1/2] =3/2

sqrt( (-9/6)^2) = ± 1.5

i.e. there are two solutions, and the positive one is conventionally referred to as the "principal root".

If you evaluate the expression using Wolfram Alpha (as suggested by user above) you can see the TWO roots illustrated in the complex plane (Argand Diagram) at the bottom of image related.

I ment at wolframalpha. Roots have two solutions.

like this

you aren't looking for an x tho

in math, when a domain isn't specified, it's assumed to be all real numbers

why not just go on wolfram alpha? tard

well i doubt at OPs level he's going to get in trouble for not using the +/- sign. i never had to write it since +/- was assumed. even when we did complex roots i.e. sqrt(-1) = +/- i

f(x)=0 and f(0/x) have different domains, they're not the same

true, here you have a source

onemathematicalcat.org/algebra_book/online_problems/dom_range_function.htm

9/6

Have y'all ever heard of complex numbers, fucking brainlets?
You all are dumb as fuck, not even right

Zero,

What mental midget fags reside here

It's +-3/2 ffs

but this isn't a complex number

> " you aren't looking for an x tho " ;

Neither the OP, nor myself, made reference to an " x " ;
..... you were the one that introduced it.

Not that it matters, x is just the "first choice littoral algebraic symbol for an unknown (or set of unknowns if there are more than one, as indeed in this specific problem).

Never said it was. But they should know about squares of negative numbers

Square roots, my bad

it can be expressed with i though. i = sqrt(-1)

1/9

Do I really have to do this

Where's the variable we're trying to solve for?

yeah but then i is squared, and then you have -1
which makes -3/2 the answer obviously

Fucking brainlet. Go to sci and argue there. That would be fun

sqrt(x^2) is the definition of absolute value. So 9/6.

go do your homework little timmy

you can also rewrite it as absolute value so its equal to |-9/6| and thats 9\6 which is 3/2...
Also you have to be at least 18 years old to post on this board

Well memed user

THE SQUARE ROOT DOES NOT APPLY TO THE NEGATIVE SINCE THE NEGATIVE IS BEING SQUARED INSIDE THE BRACKETS

So instead of going to some website that can easily do this for you in a matter of seconds you choose to go to one of those cancerous autistic places on the Internet?

> " well i doubt at OPs level he's going to get in trouble for not using the +/- sign. ..." ;

I was taught at about age 11 or 12 y.o. the importance of explicitly stating all possible roots.

At that age we would have only been graded at half marks if we only specified half of the valid solutions to a given problem.

e.g. the solution to the quadratic

x^2 - 10x + 25 = 0 is NOT just 5,

..... it is 5, or 5 there are two solutions, that both happen to have the same value.

Those two fives might in practice be two five dollar bills in your wallet. There really would be two of them.

but I like the attention...

x = goFuckYourself.exe

while that is true for all real functiones, this isn't a function (there is no x), so that doesn't apply here, sadly

yeah for a quadratics like that specify all roots. not in 5th grade problems like OPs.

±3/2 you fucking normie

it has no two solutions you idiot... the parabola is touching the x-axis in only one point (the top of paabola -> i dont know how it is called in english) so it makes only one root.
back to school nigger

Christ, Sup Forums...
Do you always have to be this dumb? That 9/6 which the rest of the problem reduces to IS NEGATIVE.
The square root of any negative number is always the absolute value of that number times the imaginary number, i.

So the answer is (3/2)i.

en.m.wikipedia.org/wiki/Imaginary_unit

>negative squared, then root

square root

What is the square root of 64?

There is no fucking i.

One of the answers -3/2, the other 3/2. Nth roots always have N answers.

Look up imaginary numbers and yes you can

There is no variable to solve so you're wrong, dumbass.

Someone doesn't know how to multiply fractions.

What a stupid faggot

Refer to this

> " while that is true for all real functiones, this isn't a function (there is no x), so that doesn't apply here, sadly " ;

I never said it was a function, it is an arithmetic expression that happens to have two real values and they ARE : -1.5 and +1.5 .

What are you op? A 12yo kiddo?

It's irrelevant you stupid cunt.

You must be trolling

Sup Forums is smart as shit i see... try calculate (3/2)! fags

Then get it right, nigger

i honestly hope you were regularly molested by your parents as a child

get the fuck back to 9gag

> "... not in 5th grade problems like OPs. " ;

I was taught it in either 5th or 6th grade - at a time when they taught mathematics properly, and I certainly would have given both roots at hat level, or been made to write out the correct solution in full as compulsory extra homework.

That was back in the day when they beat us with canes, or gym shoes, for getting the same thing wrong twice.

how's grade 9 treating you?

GUYS
r[(-9/6)^2]=1,5
The square goes inside de square root in OPs pic, that’s the order of operations
You could only cut and say it’s -1,5 if it was displayed like this r(-9/6)^2

You jackass you can't square root a negative