Operation: 777

Operation: 777

If we can meme Donald Trump's inaugeration into being delayed by a day, then
>He will be 7 decades, 7 months, 7 days of age at his inaugeration
>His inaugeration will be on the 21st; 21 is divisible by 7
>His inaugeration will be on 2017-1-21; the digits add to 14 which is divisible by 7
>His inaugeration will be on the 23rd day of the 4th month of the year 5777 in the (((jewish))) calendar; those digits add to 35 which is divisible by 7

It is crucial that this coincide with inaugeration day. Inaugeration day is a ceremony/ritual; gods love that stuff. Inaugeration day is also the day of the transfer of power. It has to be special.

Point is, Lord Kek demands that we meme Trump's inaugeration into being delayed until the 21st.

Several protest groups planning large-scale demonstrations have permits in place and have already held organizational meetings, among them the collaborative DisruptJ20. “We’re planning a series of massive, direct actions that will shut down the inauguration ceremonies and any related celebrations,” the group says. “We’re also planning to paralyze the city.”
We just have to make this go viral, get the SJWs and globalists to shut down the inaugeration on the 20th.
In doing so, the globalists and their servants will be unwittingly enhancing Lord Kek's power in memetic chaos magick.
Them shutting down the inaugeration will also give us political leverage against them.

DEUS KEK VULT!

If we pull this off, I will truly believe in Lord Kek.

if it has to be it will be, no need to do anything.

what is the problem with the math question?
It seems fine to me.

70

You can say the same thing about anything. Then you will do nothing with your life and the world will succumb to the parasites. We need to trick the SJWs into delaying the inaugeration by a day.
>bonistani education

I thought Russians were supposed to be smart.

>this is the kind of bullshit that rural and suburban retards obsess over

Yeah, did it in my head real quick and it's fine, 70 something-metres squared. I know these problems are usually not drawn to scale but this one really hurts to look at, maybe it's that? Don't see what it has to do with common core tho.

By giving the hypotenuse of the trapezium, they have made and impossible shape, and it's very obvious if you work out the length of the triangles. 2 by 5 by 8. 4 + 25 != 64, but it has to because of pythagoras.

No it's not you fucking idiot

nvm, I'm retarded. I see it now

The two triangles on the side would have to have sides of length 2 and 5, yet have a hypotenuse of length 8.

Tell me how a triangle can have a hypotenuse longer than the sum of its sides?

alright chill out Dr. Burger, fucking hell, I admit I was being retarded tho

How is the area not 70?

the problem is not the area, the problem is that the triangles, assuming right angles, are impossible. For each triangle, if the height is 5 and the width is 2 (16-12, then 2 for each triangle), the line claimed to be 8 on the test, cannot be 8. pythagoras.

They should remove either the 8s or the 16 on the drawing.

there is no such trapezoid 12+8+16+8 with height of 5. Geometrically impossible.

there is no indication of 5 being the height though since there is no right angle symbol there. logically, we should disregard the 5 and attempt to the solve with just the other dimensions?

You forgot the fact that his first press conference was 77 minutes long.

Kek, little did you know 12 is the magic number. 12 eggs in a carton, Jesus had 12 disciples, 12 months in calendar, 12 zodiac signs, the list goes on.

going by this, the area should equal 16 times the square root of 60

or 123.9354670786373

Antifa protestors will help with this. Try to meme it for them, tell them it´s a plan to have "Trump failing on DAY ONE EVERYBODY".

Infiltrate their subreddits etc. Don´t sperg out just subtly hint at this using some nice commie subversion speak.

91.22498999 units^2

Ignoring the bottom because that shape doesn't work with the bottom measurement of 16

How IS it 70, dumbfuck?
Yes it does work, you can't arbitrarily pick a random number and be like LOL IDK THIS NUMBER IS THE ONE THAT DON'T WORK CUZ I'M A KANGZ

Holt shit calm down prof. Burger

>yfw

bahah this dude comes in with some kek operation and everyones goin on about his shit common core image

>How IS it 70, dumbfuck?
well depending which part of the blatantly false representation you wish to ignore, 70 is a possible answer. It's the one you get when you dismiss the 8 and assume the dotted line to be at a right angle to the lines labeled 12 and 16 (which we assume to be parralel).
Then it's (12 * 5 ) + 2 * (2 * 5 * 1/2) = 60 + 2 * 5 = 70

>burger education

So you have a quadrilateral with sides 12, 8, 16, and 8, with the two 8-length sides being opposite. Congratulations! Now go ahead and solve it, faggot. Protip: You literally cannot.

((12+16)/2)×5

(28/2)×5

14×5=70

Oh, so in Switzerland you can just blatantly disregard some info given, and then make up some other baseless assumptions, and proceed to solve the problem? I'm surprised you guys aren't even more cucked than Sweden with that logic.
At least I'm not getting raped by a sandnigger every day.

FAKE SNEWS

well what's your result then, and how did you get to it? what's the angle between the line labeled 5 and the one labeled 12?

2x2 + 5x5 != 8x8

>flag
not surprised

seeIt is not solveable, the numbers are wrong.

a2+b2=c2
a2+52=82
a2+25=64
a2=39
a= ~6.25

Check the numbers: (12 + 6.25 + 6.25)!=16

It makes no fucking sense at all

I don't think Common Core really did anything. I think small town people use it as a channel for anti-Obama/anti-Federal sentiment

No, we must keep trump at 666

Fuck off common core shill

>It is not solveable
Correct
>the numbers are wrong.
Incorrect

>well what's your result then
There isn't one
>and how did you get to it?
I can get a range of possible results though
>what's the angle between the line labeled 5 and the one labeled 12?
I don't know. It's not specified.

He would be at 776 not 666 you fucking dumbfuck leaf.

The answer is 60. If you cant solve this simple problem you need to go back to 4th grade.
Good luck.

ofc it's not solvable, that's why you have to ignore parts of it and state the assumptions in the answer.
If you wrote "Unsolvable" into the test, you'd receive 0 points.

>I can get a range of possible results though
Well then present it. And how?

5*12 = 60

(16/2)*5 = 40
40*2 = 80

80+60 = 140

wait wrong

5*12 = 60

(2/2)*5 = 5

5*2 = 10

10+60 = 70

>gods
Your pagan rituals are fine everyone but I can't stress enough the existence of one God. Any other individual aspects are only that way to make little minded people understand God's scope.

>arbitrarily ignoring random parts
Stupid fuck.

The lower limit of possible areas approaches A=sqrt(1008)=31.749015733 from above. The upper limit of possible areas is A=40+sqrt[((20+sqrt(25+(16-sqrt39)^2))/2)(((20+sqrt(25+(16-sqrt39)^2))/2)-(sqrt(25+(16-sqrt39)^2)))(((20+sqrt(25+(16-sqrt39)^2))/2)-12)(((20+sqrt(25+(16-sqrt39)^2))/2)-8)]=82.684891941.

I will not try to understand that. I assume this is some maximum/minimum form of analysis.

also how in god's name does the shape look if you don't ignore random parts? It is certainly possible to have a shape with 4 edges with the lengths 8,12,8,16 (in that order). What is not possible is to have a line of length 5 reach from the 12 side to the 16 side (regardless of angles). Quickly drawing this thing down makes this obvious.

>tfw Sup Forums trolls it´s own faggs