You should be able to solve this

You should be able to solve this

I am sorry sensei, I can't.

what bugs me more is that nearly all the time capital letters denote corners and small letters denote lines

Is this it?

(7-4)sin(arcsin(3/7)) + 7sin((pi)-(arccos(3/4)+arccos(3/7)+arcsin(3/7)))

6.535714285714285714285714285714285714285714285714285714285...

40/7 maybe

And that is the correct way of doing it
The lines are also signed after the corner opposite to them

I google "geometry triangle theorems" and go from there.
>implying people need to actually know anything these days

Also Chio chan is cute!

Can you solve it?

I'm able to solve this. You?

What about this one, though?

180

Yes, but I'd solve it with trigonometric functions and linear algebra, instead of whichever way you're supposed to.

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It's a ten-sided figure.
Just do 180 * (10-2)

>tfw Geometry was always my worst math subject

I did well in literally everything else, but whenever shapes and angles came up my mind tended to just hit a roadblock.

I'll leave the calculations to my students for practice.

That's exactly what I got, though I used a different approach.

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Two for the price of one.

Well fuck, I thought congruent meant same shape, but can be different size.
How would you solve A if that was the case?

I got 183/28

Yeah, seems about right.

Wait, I coulda just said 4/3 = (61/7)/A

Let x^x^x... = f(x)
f(x)*Ln(x) = Ln(2)
2Ln(x) = Ln(2)
x=sqrt(2)
x^2 = 2

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>I thought congruent meant same shape, but can be different size.
Nah, you were thinking of Similar

Funny

17!
probably

oh fuck I see the funny trick now.

3x = 30; x= 10

2b = 20-10; b = 5

2c = 9-5; c = 2;

5 + (2*10) = 25;

16

First I solved the 3|7 (red) angle then the 4|3 (blue) to find the 4|7 (green) angle
that subtracted from a straight 180° line to find the purple angle
then add the purple angle back to the red angle and subtract 90° to create the teal angle
then reverse trig to find the a segment length of A given we know the long side is 7
Then I made a sub triangle which has the same angles as 3|7 and found the length of one side (green) given known lengths
reverse trig again to find the side length which corresponds to the remaining segment of A

I got lazy with my maths and there are compounding rounding errors in this so its only accurate to the tenths place I think?

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