What are some good puzzle games, Sup Forums?
Puzzle games
A
A AND 7
A, K, and 7
what if K or 7 cards have a vowel on the other side, thus breaking the rule?
All of them.
That wouldn't be against the rules. It only says vowel cards have even numbers on the other side, doesn't say other cards can't also have even numbers on the other side.
why not K? there could be an A on the other side, breaking the rule
why the 2? There is no possible thing that could be on the other side of the card that would break the rule
a and 2
Oh, right
I didn't read the rules, usually instances of this problem have "each card has a number on one side and a letter on the other side" and I got lazy
Yeah but you don't know what is behind 7 and K, a vowel could be on the back of it.
The A could have an odd number on the backside.
You seem to be confused.
"vowel cards have even numbers on the other side"
So, lets say that the second card is hypothetically K with E on the other side.
That means that there is a vowel card (E) which does not have an even number on the other side (it has a K on the other side). This breaks the rule.
Actually nevermind, I'm retarded. You're right.
All of them, if A has an odd number or a different character on the back, it breaks the rule. If K has an even number on the back, it breaks the rule, if the two has a second card under it, the second card could be breaking the rule. If the 7 has a vowel under it, it would be breaking the rule.
Just A
>if the two has a second card under it, the second card could be breaking the rule
This is the dumbest thing I've ever heard, but it's technically correct.
Anyway, Katherine
The 2 could have any other letter besides a vowel
You have to check the other card as well
It's very possible that the two is an upside-down five
A and 7. The rules doesn't say that the even number has to have a vowel necessarily.
That doesn't break the rule.
Even numbers not having a vowel is not a stated rule
The only rule is that all vowels have to have an even number on the back, a 2 is fine in all situations unless we introduce Layton-logic
A and 2
The rule just says that a vowel card has to have an even number
An even number card with a non-vowel doesn't break the rule