You should be able to solve this

You should be able to solve this

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wolframalpha.com/input/?i=triangle a=11, b=11, c=20
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8 on left, 9 on right?

answer is always 0

6+8 =14g in total
(shows as 5+9 on broken scales)

What are the scales displaying?

9,8

So 17 is the total weight

Do most Layton puzzles have solutions as bullshit as the ones posted in these threads?

How can you solve this if you don't know what the scales are displaying?

How about a question that isn't made for the sake of confusion or at least that's interesting?

Layton puzzles are always bullshit.

14g but we all know this riddle is bullshit

They can both be 9. There's nothing that says the sugar can't weigh more than 9g

So what do the scales display if I put a fucking kilogram of sugar on it? 9? Do both of the portions have the same weight?

Wait, so they literally give you one half of the solution for free?

Is this 2 ?

4? 11◄7◄5► 3 back into the hole?

Yes.

No. The answer is he hits the ball at an angle, so it only takes him two shots.

It's really lame that the explanation for the solution is a cop-out so no actual calculations are needed, because that's what 99% of players would normally attempt to do. The answer does make sense, but still.

11+7+5-3

The puzzle is worded in just the way to make the player overthink it instead of figuring out the easy solution. It's not a cop out just because you fell for it.

That is the real question. Question does not state what scales display at the moment, so answer is any pair on numbers from 0 to 9.

But it does.
>on the left scale - one gram more than the real weight
>on the right scale - one gram less than the real weight

4 strokes? 5, 5, 5, 5.

Oh, ok.

(9+1)+(9-1)=18
What am i missing?

So any number, like 4 and 6. Puzzle does not state what should be as a result, there is no sum, no explicit number to start off. And since there is no number, we can literally state that scales show any number from 0 to 9.

A 4 would still appear as a 4, and not appear to be lighter, as the problem states it does.
There's only so many numbers 0-9 that would erroneously appear to be 1 lighter or 1 heavier.

wolframalpha.com/input/?i=triangle a=11, b=11, c=20

You're weighing a different amount of sugar on each scale, you mong.

>A 4 would still appear as a 4, and not appear to be lighter, as the problem states it does.
It doesn't state that it is a result of broken displays, it just states that one shows lighter, other shows heavier. So does all Layton puzzles explained and stated this badly?

2

>So does all Layton puzzles explained and stated this badly?
Yes. Though it's easy to see what they mean if you turn off your brain.

left has to be 8 grams because if it weighed 9, then it would read 10. Similarly, right has to be 9 grams because if it weighed 8 then the scale would display 7

Hang on. The problem explains that there's something wrong with the scales.
Then it states that the weight is displayed incorrectly by a certain amount, and you think there's an arbitrary reason X not connected to the previous statement? The weight looks different because of magic?

All measuring devices suffer from a certain amount of measuring error. Maybe these scales are simply off by a gram.

Do you really need the red truth for Layton of all things?

It's both 9 I assume.

Are you guys for real? Only these 2 guys
have got it right so far.

Get your shit together Sup Forums

Right could weight 10.

>Bottom-left part of a number doesn't show up
Maximum japery right here. So we might be seeing either eight or nine on both scales.

But you kind of have to overthink it even if you have the easy solution in mind because at that point most people are still convinced they should be calculating something. When you come to the realization that there's no real calculations , it feels anticlimactic

That means one on the left weights 8. It would display a broken zero otherwise.
One on the right is either 9 or 10.
So it's 17 or 18 total.

Maybe you have to overthink if you never learned basic geometry in middle school.

But the game implies it because the scales only have a single digit, and the example used is also with a single digit, so you'll obviously start thinking in single digits.

The one of the left can also weight 7, as it would list a 8. Which would be displayed as a 9.
So in actuality we're seeing: 16, 17 and 18 as possibilities.

I should be able to move out of my patents house too, but that a'int happening either. If not solving a puzzle is the most embarrassing thing to happen to me today it'll be one of my better days.

It's the exact opposite, actually. You'd be more likely to use the same justification as the game if you didn't really understand geometry, but you considered the semantics of the problem in a different way

Honestly I didn't understand the rationale behind this puzzle. Help a brainlet out.

Since fucking when did a 5 display? OP's image only lists 9's and the 5 thing is a example on how the broken display works.

>you considered the semantics of the problem in a different way
Bravo, user, you figured out why it's a logical puzzle instead of a mathematical problem. Have a cookie.

The mass of the sugar on the left scale is any such that the final digit is 8 (broken display makes its +1 appearance 9)
The mass of the sugar on the right scale is any such that the final digit is 6 (broken display makes its -1 appearance 5)

No upper bound (such as neither pile may exceed 1 digit of measurable mass) is provided however so there are technically an inordinately large number of viable answers (limited only by the theoretical possible density of sugar in this scenario's universe or the destructibility of the scales), though the final digit of the sum of sugar on the scales in grams will always be 4. 8+6=14g is presumably the answer sought, but the problem cannot be truly solved solely on the information presented.


8g + 6g = 14g
18g + 56g = 74g
999998g + 999996g = 1999994g
autism etc

No seriously, where do the 6's and 5's come from? That's a example and not a actually displayed scale if we go only by OP's image.

The scales are shown to have just one digit display though, meaning that the only answer possible is 14

You're wrong, because it's impossible for the right scale displays the number 6 because the number formation on the left scale.

The number is 8 + 1, it's showing 9.

The way the picture shows the number it's impossible for it to be any other thing. the 5-6 thing is just an example.

Because it's somehow not possible to measure more [thing] than the display has digits for, right? I guess if my car were to hit 1,000,000 miles on a six digit odometer it will violate causality and return to a point in spacetime before it hit that millionth mile?

The scales aren't displaying 9 you danguses, the lights aren't lit up. It's just showing you which of the lights are broken.

Just the bottom one is broken.

Then OP is a fuck-up for not posting the light lit up version. As I mentioned by going only by OP's image.
You got japed by the OP and just used the Layton version like a fucking sheep. The answer if we keep to it is at best combined with the autistic math from

But if you put 18g of sugar on the scale, it will show 9g, which obviously isn't 1g more than you're weighing.

So you're saying that this layton game should have this needlessly complex answer that goes outside the bounds of the question, when a much simpler answer that's within the scale (ha) provided is very much available?

Just two, you don't even need to go into the hole triangle stuff. All you need to do is shot two times, 11 + 11. The ball will pass through the hole and fall inside it.

>OP posted a layton question
>user gets the right answer
>"you just used the Layton version like a fucking sheep"

Dude

You do actually need the hole triangle stuff, due to the last statement with the fact that going over the distance it will roll over to the other side without going into the cup.

>OP posted a layton question. Except the image doesn't display the parts necessary to actually get the layton answer.

Yes it does, that's how several people were able to get the right answer.

It'll depend on the acceleration, it could go really slow, if that's the case the ball would fall.

No, you'd only need that part if he could putt a distance of over 20 feet

It obviously won't.

It has 2 answers.

The left scale could be 7 or 8.

Circle those parts of OP's image in red if you would.
If you use the example you'll get called mean things.

That's applying a needless complexity to an otherwise simple flat assumption that the game tells you to make

okay, you're right, I skip the last bit.

The left scale can't be 7, because then it wouldn't display 1g more than the actual weight

7 + 1 = 8
8 + 1 = 9

If it's 7. Due to it listing it as +1 it's going to try to show a 8.
Because the bottom left part of the display is broken, trying to show a 8 would display a 9.
Is this so hard to understand?

you just blow in from stupid town?

You could not look up the answers or use meta knowledge?

The point is that the scale shows up as 1 more than it actually is because of the one broken light on the scale. 8 shows as 9 because the bottom left light is off. 7 would still display as 7.

there is no lit up version you dingus. You are supposed to figure out that the wrongly displayed number is a RESULT of broken part.

So the riddle is worded poorly, at best.

I already knew the answer when I wrote it

>So the riddle is worded poorly, at best.
Welcome to Professor Layton.

I'll agree that it should be worded "Because of the broken displays, the sugar being weighed is showing up..."

>it's another episode of Sup Forums lacking basic reading comprehension
sasuga

yes

>The point is that the scale shows up as 1 more than it actually is because of the one broken light on the scale

If that's the case the only answer is 18.