if you can't answer this correctly then please don't get into programming
>Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?
>Hurr durr I just learned about this topic and I want to show off on g of all places
>es.m.wikipedia.org
yes. switch to door no 2
when you first picked a door, you had a 33.3% chance of picking a car. one door having now been opened, you have a 50% chance of picking the correct door. it is to your advantage to switch your choice
stay
I already have a car, I don't have a goat tho
>he posts the spanish version
weve all scene the movie 21 with kevin spanky
>drug language
>taco
>m.wikipedia
the cancer is off the charts
we've all seen the movie "vegas baby" with kevin spacey in it
>he doesn't know how to change
>he got the chances wrong
why would you change?
1 2 3 = all doors have a 33% chance
1 2 goat = remaining choices both have a 50% chance
if i picked 1 then i have the same chance if i switch to 2
if you get 2 chances then its 2/3 chance, if you stay, your chances stay at 1/3
Irrelevant, I'm fine with a goat
Babby's first course in probability?
but you arent getting 2 chances, one choice is being removed and you get 1 lower risk chance of the same risk choices
but wouldnt you rather have 2 chances rather than 1?
in 2/3 cases your first door choice is a goat. in those cases the other goat door is guaranteed to be eliminated. hence switching is beneficial in 2/3 cases
if your first door choice is a goat then you get a goat instead of a car
no extra chances are mentioned, you pick door 1 and the fucker opens door 3. you still get one chance to pick door 1 or 2, nothing else changes.
no, i can decide to switch to the remaining door after my first choice
but door 1 never gets opened after your first choice. he never opens door 1, did you read it? theres still 2 doors left
we've all seen the movie "u wonna count cards, try atlantic city" by laurncefishbarn
go draw a tree
Are you all dumb? The car is behind one of the doors, and in a real life situation, it isn't truly random. If you had picked the correct door, it still is the correct door whether or not one of them was revealed.
I had to code it myself and run it a massive amount of itterations before I understood it
Your math teacher tells you that you can hit him 3 times. One of those hit will be an automatic detention for you. Other two will have a 50% chance of sending you to detention.
What's the chance you'll be sent to detention?
>just know what the correct door is!
0 because I'm a pacifist
>Choosing a chance to get a shitty car over delicious goat
Digusting
>he eats goat meat
I want europoors out of my Sup Forums
He's obviously trying to trick me into switching door because the currently chosen one has the car behind it. I won't fall for his trickery.
1/3 :^)
If staying your choice (door 1):
If 1 is a goat and you stay with 1: You get goat
This has a 2/3 chance of occuring
If 1 is a car and you stay with 1: You get car
This has a 1/3 chance of occuring
Therefore, if staying with 1, you have a 1/3 chance to get a car.
If changing your choice (door 1):
If 1 is a goat and you change: You get car
This has a 2/3 change of occuring also
If 1 is a car and you change: You get goat
This has a 1/3 chance of occuring
Therefore, if changing doors, you have a 2/3 chance to get a car
Therefore, changing doors gives double the chance (2/3) compared to staying doors (1/3), to get a car.
Does not matter. Yall plebs assume the door you first picked automatically has a goat
Does he always reveal a goat and offer the switch no matter what door you choose?
>muh paradoxes
can someone explain this one to me? i dont get it
>"In a race, the quickest runner can never overtake the slowest, since the pursuer must first reach the point whence the pursued started, so that the slower must always hold a lead"
43%
Literally what is an infinitesimal
if you start running at a slow speed and 5 seconds later i start running at a faster speed, i will eventually run past you
what am i missing?
But you still have that 50% if you dont switch, right?
50% chance of car being behind door 1 and 50% chance of car being behind door 2.
Since. Am from a future where I already know a goat is behind door 3, I pick door 3 first. Then, when a goat ia revealed behind one of the other two doors, I change my pick to the remaining door, guaranteeing my ownership of a new car.
Checkmate, Atheists.
no, you picked when you had a 33% chance of getting the correct one. you still have a 33% chance of picking the car, even after a goat is revealed. if you then pick again from the new situation, you have a 50% chance of being correct
muhammad get fucked!
D D D
each door has a 33% chance of having a car
you pick one
X D D
each door still has 33% chance, but the doors you did not pick, together have 66% chance
mr hall removes a door
X # D
X is still 33%
# D stil have a 66% chance, but since there is only 1 door of the set left, the door neither of you 'touched' has 66% chance to have a car behind it.
If you don't switch, you win if you picked the winning door initially (33%)
If you switch, you win if you picked a losing door initially (67%)
Write me a program to prove your correct answer then OP
Yes.
Before, you had a 2/3 chance of picking a goat. This past odd is not altered by future revelation of that one of the doors you picked was also a goat.
No matter if you picked goat A, B, or Car, in every scenario the host would be able to reveal one goat.
No matter what, your first pick had only a 1/3 chance of being a Car.
Logical contropositive of this there is a 2/3 chance that the car is in a door you didn't pick first.
Think of it like the odds of russian roulette. The falacy of saying its better to stay is like trying to compare it to a pull of the trigger that didn't shoot. So the odds of the next round are 1/5 instead of 6.
But the host didn't reveal what was in the chamber, he revealed the lack of a bullet in a nonchambered part of the cylinder. If you "know" the second pull of the revolver won't resort in a shot, and know nothing else, that doesn't change the odds that the probability of the chamber is still 1/6.
Because the measurements are done in single points while not accounting for the progress between them, which is where you will overrun the slower guy.
Best explanation, thank you. Should be at the top of the wiki article.
> Linking mexican wiki
Same.
And I could use the company.