Sum up education in your cunt with one pic

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I have the perfect picture for this

>not posting the new and improved version

we need to keep our memes pure
>>>/reddit/ with your hi-res shit

This is a downgrade.

I have one for American education.

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it's made on purpose though

fucking kek


>ubisoft

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>>>/thegallows/

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Do they have this version of ancap picardias?

This

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Real shit right here

Saved.

I don't get it

Did someone at least get in trouble for this?

Thought it would be some edgy antifa or something.

the cogs are positioned in a way that jams the machine.

If you try to turn any of the gears it'd get locked up

It doesn't work

It's pretty great though

I'm sure she is just so vapid and inane.

She probably gets off to that

>"for a faster trip do not suicide in the peak time"

i dont get it

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I'm crying

so, the joke is that it looks complicated and it is actually rather dull? I ask because i'm no programmer

Unecessarily complex. A loop would suffice.

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>tfw want to do computer science in university but shit like this puts me off

just use mod, unnecessary loops a shit

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Response and education

if you're not from UP maybe

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Overrated as fuck

>a loop would suffice

AMERICAN

EDUCATION

>what is the modulo operator

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keked

It could all be done by simply writing:

return !(userNumber % 2)

The % is the operation that gives the division remainder (also called modulo). If a number divided by 2 has a remainder 0 it is even or 1 if it's odd. You'd output the opposite of that, since 0 usually means False and 1 means True, hence the !()

bump

it shows that the dude has zero concept of math.

to determine whether a number is odd or even it simply suffices to divide it by two and check whether the remainder is one or zero.

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>they dont have ancient tech lesson

I'm angry that this took place

I always attended private schools.

The highschool was particularly regimented, with accretion of demerits leading to summary detentions, absolute clean shaven hair standards, and so forth.

>to determine whether a number is odd or even it simply suffices to divide it by two and check whether the remainder is one or zero.

Much quicker to just check if the last bit is 1 or 0.

>ubisoft
This actually explains a thing or two.

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Ever heard of n%2, mate?

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