How do you solve this?
How do you solve this?
Grayson Jones
Other urls found in this thread:
Zachary Sullivan
Bamp
Lincoln Diaz
Find the sum of N for 2/N(2+2(2i/N)-1) where i=1.
At least I think. I'm no mathemagician.
Joshua Phillips
unsolvable
Charles Allen
i said fuck math when they started putting letters in
Chase Wood
Insert a value for n or assume n is infinity.
Blake Howard
I don't know how to explain it but I am sure the answer is 21.
Eli Torres
ah i see, im gonna try with that. I thought you needed to simplify the expression first
Brayden Sullivan
I'm 14 so I don't understand some of the symbols, but try simplifying it then use a calculator
Grayson Gray
The only character you probably don't recognize is Sigma. Ʃ (the sum of)
Ryan Edwards
reported underage mothafucka
Asher Smith
..
Isaac Morales
It's funny because even though you really isn't 14, you're now gonna get your IP banned :DDDD
Xavier Rivera
assuming i is a complex number, you already cant add some of the qualities here, second if n goes to infinity, you could expand this and calculate the limit with lim n -> infinity.
Josiah Robinson
2 H_n + 8i H_n^2
H_n is the nth harmonic number
nb the harmonic series doesn't converge in inf, so I assume it's not the case here.
Juan Jones
= Sum (2/n + 8i/n^2)
= 2*n/n + 8*Sum(i)/n^2
= 2 + 8*(n*(n+1)/2)/n^2
= 2 + 4*(n+1)/n
Joshua Johnson
also, BTW, if you don't know the basics, at least learn to use wolframalpha.com
Julian Williams
fuck, I've summed over n, and not over i *sigh*. is obviously right.
Jaxon Edwards
2/n + 8*(n!)/(n*n)
Leo Hall
...
Andrew Wright
/sci/
Jackson Clark
You have to do your own homework faggot but I'll give you a hint.
Hint: You first have to prove the convergence of the series and then you have to factor n out to solve for i in order to get to the solution.
Gavin Gray
already posted by , although I agree that factoring the n/n out of n+1/n allows a simpler answer.
Christopher Reyes
Who the fuck still uses mixed fractions or whatever they're called
Matthew Cooper
It's an expression. By definition it can't be solved.
Gavin Robinson
it's a partial sum, not a series. The term "convergence" makes no sense here. If n -> inf, the sum can be treated as a limit, and the result would be just 6.
Caleb Lewis
i have no idea wtf happens here
Josiah Butler
See with the additional step
= 2 + 4*n/n + 4*1/n
= 6 + 4/n
Nolan Myers
I still dont understand it, this is how i started:
2 + 4i / n -1
= 2n/n + 4i / n -n/n
= 4i