How smart is Sup Forums?

How smart is Sup Forums?

She got 3 million more votes than he did.

Wait...what was the question?

total possibilities:

HH
HT
TH

HH only outcome that satisfies so 1/3

...

/thread

50-50 fuckwad. If the other coin already landed heads, it makes no change to the probability of the other landing heads.

could they both not be tails?
Its 1/4

who lost the election was not the question but thanks for playing, now back to your minimum wage job

Read the question again Friendo :^)

its 50% you tards

trick question, those are euros. as soon as you flip em three refugees appear, one stabs you in the the gut, one grabs the coins and the third rapes your wife

Retard detected.

>could they both not be tails?
No. At least 1 landed heads.

1/3

You're a moron. Well done.

one third
>duh
stop being a retard by posting basic shit any 5th grader knows

>Two coins, both with a 1/2 chance to land heads or tails
>One coin, stated by the problem given, lands heads
>One coin left to flip, 1/2 chance for it to land heads and complete the double-head coin flip

Chance is 1/2, or 50%.

Why would HT and TH be two separate outcomes if one is definitely landing on heads?

This guy gets it

Subtract the fraudulent votes and it's a lot closer

There are 3 outcomes possible which all contain at least 1 heads.

Heads-Heads
Heads-Tails
Tails-Heads

1 of those 3 is both heads

1 of 3

1/3

Now fuck off.

See

Because they are different outcomes.

Flip 2 coins. 4 equally probable outcomes possible:

HH
HT
TH
TT

At least 1 landed heads. Only TT no longer possible.

3 equally probable outcomes still possible:

HH
HT
TH

1/3

this was posted last week

if one coin is already decided, you're flipping only one coin you fucking retards

it's still 50/50 or 50%

See

There's Heads-Heads
Then theres Heads-Heads but in the opposite order

2/4

No, you stupid fuck. 2 coins were flipped and at least 1 landed heads.

3 equally probable outcomes satisfy this condition.

1 of those 3 is both heads.

1/3

ITT: Retards can't do basic conditional probability

See >Pic

Given that one coin landing on a surface and the other coin landing on a surface are isolated events, the chance is 1/3.

HT and TH are separate outcomes

HH is the same outcome. Imagine using a penny and a quarter.

You could get

penny = heads, quarter = heads
or
penny = heads, quarter = tails
or
penny = tails, quarter = heads

Those are the only outcomes possible that contain at least 1 heads.

1/3

kek'd

ah this thread again.
basically, one guy trolls constantly saying it one, obviously wrong, thing and Sup Forums constantly tries to talk reason to them. and it usually lasts a while because if theres one thing Sup Forums loves, its fruitless arguing.

Are you retarded or trolling?

Hey look, it's the guy this person is talking about;

Because it is two seperate events. Coin one landing heads and coin 2 landing tails is different from coin 1 landing tails and coin 2 landing heads.

TL;DR: Two isolated events make the results of the combined event unique, even though it is only the ordering that has changed.

there's the bait in this stupid retoast

it doesn't specify whether the coin is heads before or after toss

leading to 2 possible true answers

if it's determined before, it's 1/2
if it's determined after, it's 3/4

>last week
Been here for years and even back then the thread was old. People will post anything that will get them replies, despite them posting it for the hundredth time.

Anyone saying 1/2 or 50% is just dumb or trolling

Answer is 1/3

ROLL C1 REROLL C2
?? ??
/ \ / \
H? T? T? H?
/ \ / \ / \ / \
HT TH TH TH HT TH HH TH
^^

It's 1/8 learn some math.

it's obviously 3/4 if flipped at the same time.

HH
TT
HT
TH

If you flip them one at a time then 1/2.

/thread

I meant to write 1/3, you faggots are affecting me now.

...

>too dumb to understand basic probability

I'll imply he's trolling. Or are you just pretending to be retarded, user?

Commutative Property of Multiplication states that TH and HT are the same, which means you're left with only two options. 1/2.

Checkmate, faggots.

You didn't read it correctly

>multiplication

This is conditional probability, you fucking moron. The T and H just represent the sides of the coin. They're not representing numbers to be multiplied.

Please tell me you're trolling and not actually this fucking retarded.

Winrar

This is a problem of conditional probability. First, recall that the probability of the event A happening given even B has occurred is P(A|B) = |(A∩B| / |B|, where A∩B is the set of all elements common to both A and B.

Let's define our sample space as S = {(h,h), (h,t), (t,h), (t,t)}. These four outcomes exhaustively cover all of the outcomes of flipping two coins - the value of the coin on the left occupies the first entry of each ordered pair, and the second occupies the second entry.

Now we're given the event B = {(h,h), (h,t), (t,h)} has occurred; that is, we know one of the coins came up heads. By the rules of conditional probability, this event now acts as our sample space. We want to know the probability that the event A = {(h,h)} occurred. Well

P(A|B) = |A∩B| / |B| = |A| / |B| = 1/3.

You're either an idiot or knowingly deceitful. Either way fuck off to reddit.

Good man.

Bayes' theorem BTFO the 50% faggots.

Also, simulation confirms 1/3.