Guys, I need a formula to solve this and it's been too long since I studied so I don't remember, help please.
z = ((y*x)+1)2
I have these values:
z = 169
x = 3
What's the process to discover y?
If you can get something like: y = ... it would be fantastic and I'll suck your cock.
Y=((z/2)-1)/x
169 = ((y*3)+1)2
Are you seriously this underage?
thw first one did it better :3
Depends on the country youre in.
169=((y*3)+1)2
169=(3y)2
169=6y
169/6=6y/6
28.166≈y
isnt ((y*3)+1)*2= (y*3)*2+2?
Could be, but I started from the inner part of that mess.
>((Y*3)1)=3y
Also just download mathpapa it's pretty good for solving algebra related stuff
27.833333
z=(xy+1)2
z=2xy+2
z-2=2xy
(z-2)/2x=y
y=(z-2)/2x
y=(169-2)/(2*3)
y=167/6
y≈27.833
Also, the answer to x I have, it's 4. But I need the Y isolated.
didn't work, but thanks
wut
This.
nice
>y=(z-2)/2x
I've got this and tried to run on the algorithm, the answer didn't work.
PLEASE
EXCUSE
MY
DEAR
AUNT
SALLY
BECAUSE THAT OLD BITCH KEEPS FARTING AT THE DINNER TABLE
Maybe you need to write it like this?:
y=(z-2)/(2x)
Since I suppose op meant ^2 at the end of the equation I got that y=4
169=(3y+1)^2 square root of all
13=3y+1 -1 to both sides
12=3y divide both sides by 3
4=y
y=4
Think you meant to type ^2 because it equals exactly 4...
>pemdas
pemdas is regional. can only use if the equation was originally written in a country with the expectation that pemdas would be used.
You really don't need an algorithm for this, it's basic algebra. How old are you anyway?
>z=((y*x)+1)2
>169=((y*3)+1)2
>169=(3y+1)(2)
>169=6y+2
>167=6y
>167/6=y
>y=27.833
>because it equals
That's it, I forgot, but anyway I need the Y isolated, sorry for the typo. its z=((y*x)+1)2
^2
He didn't retard, you see a caret in his equation?
But its used in the US...
clearly its the method that matters.
169=2(3y+2)
169=6y+4
165=6y
27.5=y