R if S1 and S2 are open?

R if S1 and S2 are open?
R if S1 is closed and S2 open?
R if S1 is closed and S2 is closed?

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nl.wikihow.com/De-weerstand-van-een-schakeling-berekenen
falstad.com/circuit/
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Do your own homework. That shit isn't even hard.

nl.wikihow.com/De-weerstand-van-een-schakeling-berekenen

this stuff is fun, just do it yourself

falstad.com/circuit/

lol this only needs you to be able to add and multiply

youngfag detected.

R2 + 1/R1 + 1/ 1/R4+(R3+R5)

I think I got it right

Path of least resistance.

Little reminder series is Ra+Rb, parallel is (Ra+Rb)/(Ra*Rb) -> if Ra=Rb, Rtot is half of them

protip: consider wires as a 0 ohm reistors
Use your brain now

You did not

Ok i got the results if S1 and S2 are open but What happens if S1 is cloed? Is R5 than parallel to R4 and R1?

S1 closed: Rt=R2+R3

S1 shorts all other resistances out and basically removes them from the equation.

That's not how electricity works

it only shorts R5, or as a general rule any resistance parallel to it

Ok thank you user :=)
Now you can call me a retard because i am a retard

Current always takes the path of least resistance. If there's no way for current to get through a leg, current will not take it. Take a sharpie and trace the lines from source to ground.

Series: r1+r2
Parallel: (1/r1+1/r2)^-1

S1&s2 open: Rtotal=(1/r1+1/(r2+r4))^-1
S1 closed:Rtotal=(1/r1+1/r2)^-1

S2+s1 closed:(1/r1+r2/((1/r4+1/r3)^-1))^-1

is this a football pitch?

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electronics engineer here wait till you have to do 3 supply circuits. Fucken complex numbers.

You've been mistaken from the first sentence, electricity, more specifically intensity, is proportional to the resitance (duh v=r*i) so if you have 1 and 100k it doesn't all go through the 1 one.
If you're talking about feeling it it really makes it like you don't get any through your leg while holding a metal rod too, but electronics it's not electrician's safety guide, it's about micro and nano amperes

>>electronics engineer
supply is hard

pick one

i never liked Δ - Y transactions

pick one.
not sure what you mean.

you can use effects overlap, i don't know if it's the right word

resistance is futile

yea for 2 loop

v1= R1I1 (+/-) R2I2
V2= R3I2 (+/-) R4I1

i measure how hard a circuit is by the number of transistors and poles/zeros it has, not power supplies, you just need to consider them in the polarization phase, which is the easiest one (difficulty scales with nonlinear components, ie transistrs, caps...)