(QUICK

(QUICK
(WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT
(FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))
(UNDER A (RANDOM CHARACTER POSITION)))
(OR (THIS BIRD) IS GONNA (STAB YOU)))

#algorithm
#0. Copu and convert the whole input into a string
#1. Index the '(''s
#2. Find the last one
#3. Return a string until the first ')' is reached

Copy*

THAT'S NOT YOUR FAVORITE LANGUAGE

>(UNDER A (RANDOM CHARACTER POSITION)))


what did he mean by this

a random number from 0 to post.length

BIRDMIN NO

Hey Vrajesh, go write a program that does this


my favorite language is english.

i still don't get it

[X] STAB

I guess you have to parse the grammar E : '(' E ')' | '(' ')' | [a-z]+ E | [a-z]+ or something, and store the offsets in the nodes.

>an interesting knifebird challenge for once
Nice

last '(' doesn't have to be the innermost one.

When given 0, it should return the whole post.
When 1~5, it should return QUICK.
When 14, 16 or 24 it should return (A PROGRAM).

Yeah, you got a fair point

didn't quite understand the description in the op, is this it?
#include
#include
#include

char* get_word(char* s, int start) {
int i = start + 1;
while (s[i] != '(' && s[i] != ')' && s[i] != ' ' && s[i] != '\0')
i++;
char* word = malloc(i - start + 1);
strncpy(word, s + start, i - start);
word[i - start] = '\0';
return word;
}

char* get_expression(char* s, int start) {
int i = start + 1;
int depth = 1;
while (s[i] != '\0') {
i++;
if (s[i - 1] == '(')
depth++;
else if (s[i - 1] == ')' && --depth == 0)
break;
}
char* expr = malloc(i - start + 1);
strncpy(expr, s + start, i - start);
expr[i - start] = '\0';
return expr;
}

int main(int argc, char* argv[]) {
if (argc != 2) {
printf("Missing position argument\n");
return 1;
}

int pos = atoi(argv[1]);
char* result;
char* text = "(QUICK"
" (WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT"
" (FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))"
" (UNDER A (RANDOM CHARACTER POSITION)))"
" (OR (THIS BIRD) IS GONNA (STAB YOU)))";

switch (text[pos]) {
case ')':
case ' ':
while (text[pos] != '(' && text[pos] != '\0')
pos--;
case '(':
result = get_expression(text, pos);
break;
default:
while (pos > 0 && text[pos - 1] != ' ' && text[pos - 1] != '(')
pos--;
result = get_word(text, pos);
}

printf("%s\n", result);
free(result);
return 0;
}

Yep! Well done, user.

>english is not his favorite language

Where are the FPfags? I thought this was their speciality.

var post =
"(QUICK" +
" (WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT" +
" (FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))" +
" (UNDER A (RANDOM CHARACTER POSITION)))" +
" (OR (THIS BIRD) IS GONNA (STAB YOU)))";
var root = post.split(/([\n ()])/)
.reduce((state, t) => ({
start: state.start + t.length,
list: state.list.concat({
start: state.start,
len: state.start + t.length,
token: t,
}),
}), { start: 0, list: [] })
.list.filter(v => !v.token.match(/^[\n ]*$/))
.reduce((state, v) => {
if (!state.stack.length)
state.stack.unshift(state.root);
switch (v.token) {
case '(':
let exp = { start: v.start, val: [] };
state.stack[0].val.push(exp);
state.stack.unshift(exp);
break;
case ')':
state.stack[0].len = v.start + 1;
state.stack.shift();
break;
default:
state.stack[0].val.unshift(v);
break;
}
return state;
}, { root: { start: 0, len: post.length, val: [] }, stack: [] }).root;
function find(n, pos) {
return n && Array.isArray(n.val)
&& find(n.val.find(v => pos >= v.start && pos < v.len), pos) || n;
}
function print(post, n) {
console.log(post.substring(n.start, n.len));
}
print(post, find(root, 0));
print(post, find(root, 1));
print(post, find(root, 14));
print(post, find(root, 15));
print(post, find(root, 16));

What the fuck have I done.

birmin no

Where's your reference solution, stupid bird?

[USER WAS STABBED FOR THIS POST]

It's not the real bird though. This faker won't stab me.

#include
#include
#include
#include

#define NB '\0'
#define OB '('
#define CB ')'

int main(int argc, char** argv) {
char* input = "(QUICK\n (WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT\n (FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))\n (UNDER A (RANDOM CHARACTER POSITION)))\n (OR (THIS BIRD) IS GONNA (STAB YOU)))";
char* current;
char* deepest = input;
int level = 0;
int maxlevel = 0;

srand(time(NULL));
for(input + (rand() % strlen(input)); *current != NB; current++) {
if(*current == OB) {
level++;
if(level > maxlevel) {
maxlevel = level;
deepest = current + 1;
}
} else if(*current == CB) {
level--;
}
}
for(current = deepest; *current != CB && *current != NB; current++);
printf("%.*s\n",(int) (current - deepest),deepest);

return EXIT_SUCCESS;
}

I have no idea how to solve this.. I was thinking the last '(' and the ')' that follow it would be the innermost expression, am I wrong in that regard?

>am I wrong in that regard?
yes, the inner most text is the most nested one
"the last (" doesn't hold up in this example:
(((This is the inner most text))(this is the last bracket))

I literally don't know how I'm going to approach this, and I'm starting CS in college in 2 weeks time.

t-there's still enough time to kill myself right?

>t-there's still enough time to kill myself right?
yes, but you need to start doing so now

import random

a = """ (QUICK (WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT (FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST)) (UNDER A (RANDOM CHARACTER POSITION))) (OR (THIS BIRD) IS GONNA (STAB YOU)))"""

n = random.randint(0, len(a))

for i in range(n, 0, -1):
char = a[i]
if char == "(":
s = a[i+1:].split(")")[0]
break
if char == ")":
for i in range(i, len(a)):
char = a[i]
if char == "(":
s = a[i+1:].split(")")[0]
break
print n
print s

[\code]

But OP said something different here: >When 1~5, it should return QUICK

This means that Op actually wants the outermost word or expression, or am I wrong?


This is hard to understand..

What's actually the correct way to approach this problem? I'm too scared to kill myself.

I don't get it.
say, if I'm given 7 as an index
then the innermost is the middle from the 7th index to the last index?
so (n + last index) / 2

help you stupid fuckin bird

Is this Lisp?

import Data.List (maximumBy)
import Data.Ord (comparing)

import Text.Parsec
import Text.Parsec.String

expr :: Int -> Parser (Int, String)
expr d = do
prefix

Here's a Ruby version, I hope I understood this correctly..

#init
input = %q[(QUICK
(WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT
(FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))
(UNDER A (RANDOM CHARACTER POSITION)))
(OR (THIS BIRD) IS GONNA (STAB YOU)))] . gsub("\n", '')
output = ""
i_max = input.length
cnt, cnt_max, i = 0, 0, 0

# random start --> find last opening bracket
puts "Starting at position #{i = rand(i_max)}"
while input[i] != "(" and i > 0 do i -= 1 end

# find innermost expression
input[i..-1].each_char do |c|
if c == "(" then
cnt += 1
if cnt > cnt_max then
cnt_max = cnt
output = ""
end
elsif c == ")" then
cnt -= 1
break if cnt == 0
else
output

I just noticed, that "i_max" is toally senseless here.. meh.

Refactored my code for the lulz:

r, c, c2, i = '', 0,0,0
input = %q[(QUICK (WRITE (A PROGRAM) IN (YOUR FAVORITE
LANGUAGE) THAT (FINDS THE INNERMOST (WORD OR EXPRESSION)
OF(THIS POST)) (UNDER A (RANDOM CHARACTER POSITION)))
(OR (THIS BIRD) IS GONNA (STAB YOU)))] . gsub("\n", '')

puts "Starting at position %i" % (i = rand(input.length))
while input[i] != "(" and i > 0 do i -= 1 end
input[i..-1].each_char do |j|
c += (j == '(' ? 1 : (j == ')' ? -1 : (r c2 ? (c2 = c; r = ''):'')
end
p r

When 7, it's the whole post.

For the string ((a) b):
0 is ((a) b),
1 is (a)"
2 is a
3 is (a)
4 is ((a) b)
5 is b
6 is ((a) b)

Is the innermost expression supposed to be WORD OR EXPRESSION if the position is 0?

Under the position 0 there is only an expression.

As in should my program output "(WORD OR EXPRESSION)" as the innermost loop?

It should output that if the position lands in one of its parenthesis or a space.

So if, assuming the function works correctly, if the random number generated is 0, the innermost expression would be "(WORD OR EXPRESSION)"?

No. "(WORD OR EXPRESSION)" is not located under the position 0.

this problem makes no sense
I guess I getting stabbied.

Post a problem that makes sens better time, kiwibird

Ok almighty bird, I think I got it.
What you call "innermost" is the smallest word or expression the pointer is on.
If on a word, then it returns the word and if on a space or a parenthesis it returns the parenthesis and all that is it in.
tl;dr return smallest grammar token the cursor is on.
Have I successfully understood your question, Stabby Birdy?

Yes.

Although "the parenthesis and all that is it in" is not a single grammar token, you got it.

>stupid bird
kek

Woah that was totally not what I understood, I thought OP just wanted the words inside the innermost loop of the entire string.

I doubt that's it. That's way too easy.

Holy shit, it was a cat the whole time.

Could it be?

fuck this thread

#include
#include
#include
using namespace std;

int main(int argc, char *argv[])
{
string input = "(QUICK(WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT(FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))(UNDER A (RANDOM CHARACTER POSITION)))(OR (THIS BIRD) IS GONNA (STAB YOU)))";
int position = atoi(argv[1]);
int new_pos = 0;

string::iterator it;
for(it = input.begin() + position; it != input.begin(); --it) {
if(*it == '(' || *it == ')')
break;
++new_pos;
}
for(it = input.begin() + (position - new_pos) + 1; it != input.end(); ++it) {
if(*it == ')' || *it == '(')
break;
cout

>C++ doesn't have a trim function

>using namespace std;

(QUICK
(WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT
(FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))
(UNDER A (RANDOM CHARACTER POSITION)))
(OR (THIS BIRD) IS GONNA (STAB YOU)))


$res: STAB YOU